Below is the XMl File -
<Chapters>
<Chapter n="1">
<Desc>....</Desc>
<References>
<BookRef>HTML : in 21 Days</BookRef>
<Page>12, 13</Page>
<BookRef>HTML : Unlimited</BookRef>
<Page>21, 22</Page>
<BookRef>The Complete Reference - HTML</BookRef>
<Page>32-35</Page>
</References>
</Chapter>
<Chapter n="2">
<Desc>....</Desc>
<References>
<BookRef>HTML : in 21 Days</BookRef>
<Page>52, 53</Page>
<BookRef>The Complete Reference - HTML</BookRef>
<Page>132-145</Page>
<BookRef>The Complete Reference - Javascript</BookRef>
<Page>132-145</Page>
</References>
</Chapter>
</Chapters>
I am trying to list - all the containing HTML
word using /Chapters/Chapter/References[BookRef contains text 'HTML']/BookRef
But all are being displayed...!! What will be the XQuery to retrieve the same?
Try the following one:
/Chapters/Chapter/References/BookRef[. contains text 'HTML']
Otherwise, all References
nodes will be returned that have a BookRef
node containing HTML
, and the following step will return all BookRef
nodes (ie, you lose the information which of the BookRef nodes had the searched token).
您要 :
/Chapters/Chapter/References/BookRef[contains(., 'HTML')]
使用XPath = /Chapters/Chapter/References/BookRef[contains(., 'HTML')]
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