I have the following macro.
#define STRING_STREAM( data ) \
( ( (std::ostringstream&) \
( std::ostringstream( ).seekp( 0, std::ios_base::cur ) << data ) ).str( ) )
I am trying to overload << for an enum:
std::ostringstream& operator<<( std::ostringstream& oStrStream, TestEnum& testEnum )
{
oStrStream << "TestEnum";
return oStrStream;
}
When I call STRING_STREAM( testEnum ), it doesn't use the overloaded <<. It prints enums number value.
std::ostream& operator<<( std::ostream& oStrStream, const TestEnum testEnum )
{
oStrStream << "TestEnum";
return oStrStream;
}
The problem is that the overloaded << operator is expecting an argument of..
new ostringstream()
but you're giving it the argument..
ostringstream()
This is not being matched by the overloaded function.
In my example, I used auto_ptr to automatically deallocate the ostringstream after it goes out of scope. This allows us to use a macro to perform our function without memory leaks.
#include<sstream>
#include<iostream>
#define STRING_STREAM( data ) \
((ostringstream&)( *( auto_ptr<ostringstream>(new ostringstream()) ) << data)).str()
using namespace std;
enum TestEnum { ALPHA, BETA };
ostringstream& operator<<( ostringstream& oss, TestEnum testEnum ){
oss << "TestEnum";
return oss;
}
int main(){
cout << STRING_STREAM( ALPHA ) << endl;
}
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