I'm reading some source code in stl_construct.h, In most cases it has sth in the <> and i see some lines with only " template<> ...
". what's this?
这意味着接下来是模板专业化 。
Guess, I completely misread the Q and answered something that was not being asked.
So here I answer the Q being asked:
It is an Explicit Specialization with an empty template argument list.
When you instantiate a template with a given set of template arguments the compiler generates a new definition based on those template arguments. But there is a facility to override this behavior of definition generation. Instead of compiler generating the definition We can specify the definition the compiler should use for a given set of template arguments. This is called explicit specialization .
The template<>
prefix indicates that the following template declaration takes no template parameters.
Explicit specialization can be applied to:
It's a template specialization where all template parameters are fully specified, and there happens to be no parameters left in the <>
.
For example:
template<class A, class B> // base template
struct Something
{
// do something here
};
template<class A> // specialize for B = int
struct Something<A, int>
{
// do something different here
};
template<> // specialize both parameters
struct Something<double, int>
{
// do something here too
};
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