I tried $this->
but could not assign a value to $first_name and $last_name
variable. Without removing static feature of the function and without inserting static feature to variables, how can I echo full_name()
? Here is the code :
<?php
class User {
public $first_name;
public $last_name;
public function full_name() {
if(isset($this->first_name) && isset($this->last_name)) {
return $this->first_name . " " . $this->last_name;
} else {
return "No name!";
}
}
public static function verify() {
$this->first_name = "firstname";
$this->last_name = "last_name";
}
}
$user = new User();
User::verify();
echo $user->full_name()
?>
You can't. Why not make verify
a member function and call it like
$user->verify();
Another alternative would be to pass the user into the verify function, like this:
public static function verify( $user ) {
$user->first_name = 'firstname';
$user->last_name = 'last_name';
}
and call like so:
User::verify($user)
You can't really... other then using the singleton pattern, which rather defeats the point of a static function.
The basic idea is that a static function doesn't require an instance, but what you're trying to do does.
I'd suggest verifying the data in a non-static setter function, or in the constructor. Or, if needs must, add a public method verify that isn't static.
Think about it: statics don't need an instance, so what are you verifying, if there is no instance (and therefore no " $this
").
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.