How can I render template tags from a view in Django

Question

I need to escape just part user input for output. For example

Hey a status update for <a href="/profile/2353">@Friend Name</a> 

I just need to escape the link part of text in case someone does something like

<h1>HaCkEDED!!!!</h1>

So I can't escape the entire block. So I tried this

'{%% autoescape off %%} <a href="/profile/%s">%s</a>{%% endautoescape %%}' % (tag, at)

When I send this to output in the browser here is what I get

 {% autoescape off %} <a href="/profile/2353">@Friend Name</a>{% endautoescape %}

How can I get the autoescape to work? I can't use a separate variable and put

{{ tag | safe }}

because one post might have multiple tags and the tags will be in different spots. So how can I get Django to let me output one of its templates?

Answer 1

我不确切地知道你要做什么，但在视图中你可以使用django.utils.safestring.mark_safe将项目标记为不需要自动django.utils.safestring.mark_safe 。

Answer 2

我认为使用自定义模板标签或过滤器更容易，可能使用一些可以识别标签的正则表达式 。