My table
ANONYMOUS
ONE TWO
1 2
2 1
1 2
3 1
Now i want to select distinct set of one and two. My selected list should be
ANONYMOUS
ONE TWO
1 2
3 1
Your question isn't very clear, but I guess you mean this:
SELECT DISTINCT one, two
FROM yourtable AS T1
WHERE one <= two
OR NOT EXISTS
(
SELECT *
FROM yourtable AS T2
WHERE T1.one = T2.two
AND T1.two = T2.one
)
It finds rows with (one, two)
where the reversed pair (two, one)
does not exist. If both exist, it chooses the pair such that one < two
. It also selects rows where the values are equal.
See it working online: sqlfiddle
If you would prefer to use a JOIN
instead of NOT EXISTS
you can do that:
SELECT DISTINCT T1.one, T1.two
FROM yourtable AS T1
LEFT JOIN yourtable AS T2
ON T1.one = T2.two
AND T1.two = T2.one
WHERE T1.one <= T1.two
OR T2.one IS NULL
See it working online: sqlfiddle
SELECT DISTINCT a.*
FROM `ANONYMOUS` a
LEFT JOIN `ANONYMOUS` b ON (a.one=b.two and a.two=b.one)
WHERE b.one is null or a.one<b.one
ORDER BY 1,2
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