I am creating a simple spring mvc app. How can I configure the spring DispatcherServlet to accept url pattern like below.
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>SpringMVC</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
Currently I am getting below warning on starting the app.
WARNING: No mapping found for HTTP request with URI [/SpringMVC/] in DispatcherServlet with name 'spring'
spring-servlet.xml (I have added the default servlet handler as well)
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/jee
http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">
<context:annotation-config />
<context:component-scan
base-package="com.springapp" />
<mvc:default-servlet-handler/>
<bean id="messageSource"
class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="classpath:resources/messages" />
<property name="defaultEncoding" value="UTF-8" />
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
First of all, your web.xml should contain DispatcherServlet mapping (you can provide dispatcher-servlet.xml file location or use default):
<servlet>
<servlet-name>dispatcher-servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher-servlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
add this to your spring-servlet.xml file:
<mvc:annotation-driven/>
And major step,you should create controller which will be mapped to your path /SpringMVC eg
package com.springapp.controllers;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
@Controller
@RequestMapping("/SpringMVC")
public class MyController{
@RequestMapping(method= RequestMethod.GET)
public ModelAndView springMvcTest(ModelMap modelMap){
return new ModelAndView("test");
}
}
Try to use one of the following:
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/SpringMVC/*</url-pattern>
</servlet-mapping>
Or:
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>*.form</url-pattern>
</servlet-mapping>
You have to map this url in controller as follows:
@RequestMapping("/SpringMVC")
public ModelAndView index(HttpServletRequest req,HttpServletResponse){
// ur business logic
return new ModelAndView("index");
}
in web xml
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
and in your controller:
@Controller
@RequestMapping("SpringMVC")
public class MyController {
Logger logger = LoggerFactory.getLogger(MyController.class);
@Autowired
private ContentService contentService;
@RequestMapping(value = "/index", method = RequestMethod.GET)
public String createForm(@RequestParam("user") String user, @RequestParam("requestId") String requestId, Model uiModel) {
//TODO
return "index";
}
and then your url would be ... localhost:port/SpringMVC/index
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