I have this sql that is made by help of others.
$sql ="
select e.*, i.*, group_concat( t.tag separator ',') as tag_list
from nv_entries e
JOIN nv_tags t on t.entrie_id = e.id
LEFT JOIN nv_images i on i.entrie_id = e.id
where t.tag in ( $tag_list )
group by e.id
having count(t.id) = $num_tags ";
The result is this (i only show one entrie here, could be more):
[1] => Array
(
[id] => 2
[band] => Kids for Cash
[album] => No More Walls E.P.
[label] =>
[year] => 1986
[text] => Text about album kids for cash.
[entrie_id] => 2
[source] => img02_9lch1.png
[tag_list] => tree
)
For the tags, i have to show all tags that a entrie has and highlight the tags that where used to get the result. In this case [tag_list] => tree
only shows one tag, the one that was used in the search field. My question is, how can i get a result like this?:
...
[tag_list] => tree, green, foo, bar
[used_tags] => tree
)
As a array is also good, but then please also an array when it's just one item.
If I understood correctly use >= in the having condition
$sql ="
select e.*, i.*, group_concat( t.tag separator ',') as tag_list
from nv_entries e
LEFT JOIN nv_images i on i.entrie_id = e.id
JOIN nv_tags t on t.entrie_id = e.id
where t.tag in ( $tag_list )
group by e.id
having count(t.id) >= $num_tags ";
ADD
subquery approach:
$sql ="
select e.*, i.*, group_concat( t.tag separator ',') as tag_list
from nv_entries e
JOIN nv_tags t on t.entrie_id in (
select se.id
from nv_entries se
JOIN nv_tags st on st.entrie_id = se.id
where st.tag in ( $tag_list )
group by se.id
having count(st.id) >= $num_tags
)
LEFT JOIN nv_images i on i.entrie_id = e.id
WHERE 1
group by e.id
";
Into subquery I get the ID list of entrie havin at least requested tags, then in main query I get all infox
ADD fixed query (see asker comment)
subquery approach, fix the lost join between "e" and "t" :
$sql ="
select e.*, i.*, group_concat( t.tag separator ',') as tag_list
from nv_entries e
JOIN nv_tags t on t.entrie_id = e.id
LEFT JOIN nv_images i on i.entrie_id = e.id
WHERE e.id in (
select se.id
from nv_entries se
JOIN nv_tags st on st.entrie_id = se.id
where st.tag in ( $tag_list )
group by se.id
having count(st.id) >= $num_tags
)
group by e.id
";
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