I have a class (that I cannot modify) that simplifies to this:
public class Foo<T> {
public static string MyProperty {
get {return "Method: " + typeof( T ).ToString(); }
}
}
I would like to know how to call this method when I only have a System.Type
ie
Type myType = typeof( string );
string myProp = ???;
Console.WriteLinte( myMethodResult );
What I've Tried:
I know how to instantiate generics classes with reflection:
Type myGenericClass = typeof(Foo<>).MakeGenericType(
new Type[] { typeof(string) }
);
object o = Activator.CreateInstance( myGenericClass );
However, is this proper to instantiate a class since I am using the static property? How do I gain access to the method if I can't compile time cast it? (System.Object does not have a definition for static MyProperty
)
Edit I realized after posting, the class I'm working with is a property, not a method. I apologize for the confusion
The method is static, so you don't need an instance of an object. You could directly invoke it:
public class Foo<T>
{
public static string MyMethod()
{
return "Method: " + typeof(T).ToString();
}
}
class Program
{
static void Main()
{
Type myType = typeof(string);
var fooType = typeof(Foo<>).MakeGenericType(myType);
var myMethod = fooType.GetMethod("MyMethod", BindingFlags.Static | BindingFlags.Public);
var result = (string)myMethod.Invoke(null, null);
Console.WriteLine(result);
}
}
Well, you don't need an instance to call a static method:
Type myGenericClass = typeof(Foo<>).MakeGenericType(
new Type[] { typeof(string) }
);
Is OK... then, simply:
var property = myGenericClass.GetProperty("MyProperty").GetGetMethod().Invoke(null, new object[0]);
should do it.
typeof(Foo<>)
.MakeGenericType(typeof(string))
.GetProperty("MyProperty")
.GetValue(null, null);
You need something like this:
typeof(Foo<string>)
.GetProperty("MyProperty")
.GetGetMethod()
.Invoke(null, new object[0]);
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