How to specify path using open file dialog in vb.net?

Question

In the first start of my application I need to specify a path to save some files to it. But in the open file dialogue it seems like that I have to select a file to open. How can I just specify a folder without oppening a file like C:\config\

Here is my code

If apppath = "" Then
        Dim fd As OpenFileDialog = New OpenFileDialog()
        fd.Title = "Select Application Configeration Files Path"
        fd.InitialDirectory = "C:\"
        fd.Filter = "All files (*.*)|*.*|All files (*.*)|*.*"
        fd.FilterIndex = 2
        fd.RestoreDirectory = True
        If fd.ShowDialog() = DialogResult.OK Then
            apppath = fd.FileName
        End If
        My.Computer.FileSystem.WriteAllText(apppath & "apppath.txt", apppath, False)
    End If

I need to select a file in order for it to work, but I just want to select a folder. So what's the solution?

Answer 1

You want to use the FolderBrowserDialog class instead of the OpenFileDialog class. You can find more information about it here:

http://msdn.microsoft.com/en-us/library/system.windows.forms.folderbrowserdialog(v=vs.110).aspx

For instance, you could do this:

If apppath = "" Then
    Dim dialog As New FolderBrowserDialog()
    dialog.RootFolder = Environment.SpecialFolder.Desktop
    dialog.SelectedPath = "C:\"
    dialog.Description = "Select Application Configeration Files Path"
    If dialog.ShowDialog() = Windows.Forms.DialogResult.OK Then
        apppath = dialog.SelectedPath
    End If
    My.Computer.FileSystem.WriteAllText(apppath & "apppath.txt", apppath, False)
End If

Answer 2

If I understand correctly, you want to let the user choose a folder. If that is the case, then you want to use FolderBrowserDialog instead of OpenFileDialog.

Answer 3

Dim filedialog As New OpenFileDialog
filedialog.IntialDirectory = Application.StartupPath
filedialog.ShowDialog()

Answer 4

Or you can simply just make it less lines and very simple.

link: http://i.imgur.com/bMq0HNz.png

Start your dialog with a click:

Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
    FolderBrowserDialog1.ShowDialog()
End Sub

Add if you want to show the actual path that you choose from your dialog

Private Sub FolderBrowserDialog1_Disposed(sender As Object, e As EventArgs) Handles Button1.Click
    TextBox1.Text = FolderBrowserDialog1.SelectedPath.ToString
End Sub

Answer 5

Use To:

Dim openFD As New OpenFileDialog()
Dim Directory As string = openFD.FileName

Answer 6

Try this

Private Sub BtnOpen_Click(sender As Object, e As EventArgs) Handles BtnOpen.Click
        Dim openFileDialog1 As New OpenFileDialog()

        openFileDialog1.InitialDirectory = "x_pathfileforsend"
        openFileDialog1.Filter = "txt files (*.txt)|*.txt|*.zip|*.rar|*.ico|*.exe|*.png|*.bmp|All files (*.*)|*.*"
        openFileDialog1.FilterIndex = 5
        openFileDialog1.RestoreDirectory = True

        If openFileDialog1.ShowDialog() = DialogResult.OK Then
            txtpath.Text = openFileDialog1.FileName
        End If
        openFileDialog1.Dispose()

    End Sub