PHP preg_replace number of digits

Question

i have this:

preg_replace('/(\d{1}|\d{2})/gi', '$1', 'some number');

If text is one digit number $1 returns one digit number, if it is 2 digit it return 2 digit number...., but I need to returned number was always been 2 digit:

1 => 01 
2 => 02
...
10 => 10
...
99 => 99

How can I do that?

Answer 1

Use str_pad(). It's a lot cheaper. http://php.net/str_pad

Answer 2

why so complex? KISS and use str_pad

echo str_pad($input, 2, "0", STR_PAD_LEFT);

Answer 3

您的意思是这样吗？使用e修饰符，使用preg_replace函数执行php代码，以及满足您要求的任何str_pad或sprintf 。

preg_replace('/(\\d{1}|\\d{2})/ie', 'sprintf("%02d",$1)', 'some number');

Answer 4

Please use str_pad() . The e modifier is DEPRECATED as of PHP 5.5.0 and should be avoided.