How do I match a tag containing only the stated class, not any others, using BeautifulSoup?
Question
Is there a way to use BeautifulSoup to match a tag with only the indicated class attribute, not the indicated class attribute and others? For example, in this simple HTML:
<html>
<head>
<title>
Title here
</title>
</head>
<body>
<div class="one two">
some content here
</div>
<div class="two">
more content here
</div>
</body>
</html>
is it possible to match only the div with class="two" , but not match the div with class="one two" ? Unless I'm missing something, that section of the documentation doesn't give me any ideas. This is the code I'm using currently:
from bs4 import BeautifulSoup
html = '''
<html>
<head>
<title>
Title here
</title>
</head>
<body>
<div class="one two">
should not be matched
</div>
<div class="two">
this should be matched
</div>
</body>
</html>
'''
soup = BeautifulSoup(html)
div_two = soup.find("div", "two")
print(div_two.contents[0].strip())
I'm trying to get this to print this should be matched instead of should not be matched .
EDIT: In this simple example, I know that the only options for classes are "one two" or "two" , but in production code, I'll only know that what I want to match will have class "two" ; other tags could have a large number of other classes in addition to "two" , which may not be known.
On a related note, it's also helpful to read the documentation for version 4 , not version 3 as I previously linked.
2 answers
solution1
4 ACCPTED 2012-07-16 16:59:45
Try:
divs = soup.findAll('div', class="two")
for div in divs:
if div['class'] == ['two']:
pass # handle class="two"
else:
pass # handle other cases, including but not limited to "one two"
solution2
0 2012-07-16 17:01:16
Hope, below code helps you. Though I didn't try this one.
soup.find("div", { "class" : "two" })
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