When I echo['time']
from the Database i get for example
2012-07-21 17:00:00
my question is how should I show only the hours and minutes for every timestamp I get? (17:00)
You can select it as:
SELECT TIME_FORMAT(`dateColumn`, '%H:%i') FROM ...
or use strtotime
as mentioned in other answers.
If you did want the full time with seconds, you could also use:
SELECT TIME(`dateColumn`) FROM ...
See http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
You could do what Kris said echo date('H:i', strtotime('2012-07-21 17:00:00'));
but It is better practice to process from MySQL if possible,
select date_format(time, '%H:%i') from table;
shoul retrieve the data and format it to you good to go!
echo date('H:i', strtotime($row['time']));
或者您可以使用datetime函数在sql查询中进行格式化
echo date('H:i', strtotime('2012-07-21 17:00:00'));
I use my own code. try this.. follow these steps:-
1. Select time from database table assuming:- $time = $row['time'];
2. create a php file with the name :- "time.php"
3. paste the following code into time.php
<?php
$ct= date('Y-m-d H:i:s');
$now = new DateTime("$ct");
$ref = new DateTime("$time");
$diff = $now->diff($ref);
$y=$diff->y;
$m=$diff->m;
$d=$diff->d;
$h=$diff->h;
$i=$diff->i;
$s=$diff->s;
if($m>12)
{
echo $y;
echo " year ago";
}
elseif($m<1 && $d<1 && $h<1 && $i<1 && $s<60)
{
echo $s;
echo " sec ago";
}
elseif($m<1 && $d<1 && $h<1 && $i<60)
{
echo $i;
echo " mins ago";
}
elseif($m<1 && $d<1 && $h<48)
{
echo $h;
echo " hrs ago";
}
elseif($m<1 && $d<30 && $h<24)
{
if($d==1)
{
echo 24+$h." hrs ago";
}
else
{
echo $d;
echo " days ago";
}
}
elseif($m<=12)
{
if($m > 0)
{
echo $m;
echo " Month ago";
}
else
{
echo $d;
echo " days ago";
}
}
?>
<?php include "time.php";?> //use include/require function where you want to display time ago...
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