Differences between "java -cp" and "java -jar"?

Question

What is the difference between running a Java application with
java -cp CLASSPATH and java -jar JAR_FILE_PATH ? Is one of them preferred to the other for running a Java application? I mean which one of these ways is more expensive for JVM (according to their machine resources usage)?

Which one will cause JVM to spawn more threads while trying to run the application?

Answer 1

I prefer the first version to start a java application just because it has less pitfalls ("welcome to classpath hell"). The second one requires an executable jar file and the classpath for that application has to be defined inside the jar's manifest (all other classpath declaration will be silently ignored...). So with the second version you'd have to look into the jar, read the manifest and try to find out if the classpath entries are valid from where the jar is stored... That's avoidable.

I don't expect any performance advantages or disadvantages for either version. It's just telling the jvm which class to use for the main thread and where it can find the libraries.

Answer 2

With the -cp argument you provide the classpath ie path(s) to additional classes or libraries that your program may require when being compiled or run. With -jar you specify the executable JAR file that you want to run.

You can't specify them both. If you try to run java -cp folder/myexternallibrary.jar -jar myprogram.jar then it won't really work. The classpath for that JAR should be specified in its Manifest, not as a -cp argument.

You can find more about this here and here .

PS: -cp and -classpath are synonyms.

Answer 3

When using java -cp you are required to provide fully qualified main class name, eg

java -cp com.mycompany.MyMain

When using java -jar myjar.jar your jar file must provide the information about main class via manifest.mf contained into the jar file in folder META-INF :

Main-Class: com.mycompany.MyMain

Answer 4

java -cp CLASSPATH is necesssary if you wish to specify all code in the classpath. This is useful for debugging code.

The jarred executable format: java -jar JarFile can be used if you wish to start the app with a single short command. You can specify additional dependent jar files in your MANIFEST using space separated jars in a Class-Path entry, eg:

Class-Path: mysql.jar infobus.jar acme/beans.jar

Both are comparable in terms of performance.

Answer 5

Like already said, the -cp is just for telling the jvm in the command line which class to use for the main thread and where it can find the libraries (define classpath). In -jar it expects the class-path and main-class to be defined in the jar file manifest. So other is for defining things in command line while other finding them inside the jar manifest. There is no difference in performance. You can't use them at the same time, -jar will override the -cp.

Though even if you use -cp, it will still check the manifest file. So you can define some of the class-paths in the manifest and some in the command line. This is particularly useful when you have a dependency on some 3rd party jar, which you might not provide with your build or don't want to provide (expecting it to be found already in the system where it's to be installed for example). So you can use it to provide external jars. It's location may vary between systems or it may even have a different version on different system (but having the same interfaces). This way you can build the app with other version and add the actual 3rd party dependency to class-path on the command line when running it on different systems.

Answer 6

There won't be any difference in terms of performance. Using java - cp we can specify the required classes and jar's in the classpath for running a java class file.

If it is a executable jar file . When java -jar command is used, jvm finds the class that it needs to run from /META-INF/MANIFEST.MF file inside the jar file.