how can i put the value of “value” field in a form where input type is checkbox from database?

Question

i tried alot in order to fetch values from database and put it in check-box array but failed.Please help!!

* img[] comes out to be empty all the time like no value is going into it when ever i call that part using $_POST(['img'])!!* here's my code:

   echo " <h2>Select image to delete: <h2>";
   $s = mysql_query("SELECT * FROM image WHERE u_id = '$u_id'");
   $num = mysql_num_rows($s);

   if($s)
   { 
      ?>
   <form name="f1" method="post" action=""> 
      <?php
    while($row = mysql_fetch_array($s))
    { 
      ?>      
    <input type="checkbox" name="img[]" value="<?php $row['path'] ;?>" />
    <img width="100" src="<?php echo $row['path']." ";?>">
    <?php                 
    }
    ?>
       <br />
       <br />
       <input type="submit" name= "subDel" value = "Delete" />
       </form>
     <?php

    } 

Answer 1

What about this? :)

<input type="checkbox" name="img[]" value="<?php $row['path'] ;?>" />

=>

    <input type="checkbox" name="img[]" value="<?php ECHO $row['path'] ;?>" />

Answer 2

Retrive post Data in PHP by using $_POST['variableName'] - no brackets, case DOES matter

In your case, $_POST['img'] is of type array . There is NO value for unchecked items. If nothing checked, your post variable is empty or even undefined (didn't test it yet).

Access your values by

if (array_key_exists($index, $_POST['img']) == true) {
    // $index is checked
    $doSomething = $_POST['img'][$index];
}