if (myCondition1 && myCondition2 && myCondition3)
{
...
}
I wrote this code and run successfully. but I got warning about part of (...). The warning is "Dead code". It is just interesting to me. Do u have any idea? thank u
"Dead code" is code that will never be executed. Most likely one of your conditions is hard-coded to false
somewhere, making the conditional inside the if
always false.
Dead code means it is never going to execute. Eg
void someMethod() {
System.out.println("Some text");
return;
System.out.println("Another Some text"); // this is dead code, because this will never be printed
}
Same in case of your condition checking eg
String obj = "";
if(obj == null && obj.equals("")) { // here you get warning for Dead code because obj is not null and first condition is false so obj.equals("") will never evaluate
}
Your code inside the block is never reached. The reason is most likely that one of the conditions is always false.
如果myCondition1,myCondition2和myCondition3中的一个或多个始终为false(如私有const bool myCondition1 = false;)那么if中的代码将永远不会被执行。
This could occur for a number of reasons. Either the whole of the if
block is dead , caused by something like the following:
boolean condition1 = true;
boolean condition 2 = !condition1;
if(condition1 && condition2) {
//This code is all dead
Foo f = fooFactory();
f.barr(new Bazz());
}
Or you unconditionally leave the if
block using something like return
, break
or continue
, as shown below:
for(Foo f : foos) {
if(true) {
f.barr(new Bazz());
break;
//Everything after here is dead
System.out.println("O noes. I won't get printed :(");
}
}
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