I don't want to use something like this :
Logger.getLogger(MyClass.class).info("Info message");
each time I want to log something.
I've tried to implement a logging service that has methods like :
public void info(final Object aMessage, final Object aSender);
This allows me get Logger instance based on sender's class, but it hides the method and line of the log source class.
I know about alternatives like AOP or Slf4j. The first one is not exactly I want, the second one introduces something similar to the first line of code :
LoggerFactory.getLogger(HelloWorld.class).info("Info message");
So, my concern is not about hiding Log4j dependency, it's about unifying logging calls through the whole application, like this :
//loggingController instance was injected previously
loggingControler.info("Info message",this);
Is there any way to implement this ?
Ok, seems that there is at least one way to resolve the issue :
For example there are LoggingService and LoggingController. The first one works directly with Log4j, the second one is just a layer between service and the whole application.
public class LoggingService implements ILoggingService{
//other methods here.
@Override
public void warn(final Object aMessage, final Object aSender, final Throwable aThrowable) {
log(aMessage, aSender, Level.WARN, aThrowable);
}
private void log(final Object aMessage, final Object aSender, final Level aLevel, final Throwable aThrowable) {
final String className = getClassNameBy(aSender);
Logger.getLogger(className).log(className, aLevel, aMessage, aThrowable);
}
}
public class LoggingController implement ILoggingController{
//logging service is injected previously
@Override
public void warn(final Object aMessage, final Throwable aThrowable) {
loggingService.warn(aMessage, this, aThrowable);
}
}
So, in this case you allow the user to log something using :
loggingController.warn("A warning", null);
Using this way:
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.