Loop print through two lists to get two columns with fixed(custom set) space between the first letter of each element of each list

Question

Suppose I have these two lists:

column1 = ["soft","pregnant","tall"]
column2 = ["skin","woman", "man"]

How do I loop print through these two lists while using a custom, fixed space(say 10, as in example) starting from the first letter of each element of the first list up to the first letter of each element of the second list?

Example output of a set spacing of 10:

soft      skin
pregnant  woman 
tall      man

Answer 1

Easily done with the string formatting ,

column1 = ["soft","pregnant","tall"]
column2 = ["skin","woman", "man"]

for c1, c2 in zip(column1, column2):
    print "%-9s %s" % (c1, c2)

Or you can use str.ljust , which is tidier if you want to have the padding be based on a variable:

padding = 9
for c1, c2 in zip(column1, column2):
    print "%s %s" % (c1.ljust(padding), c2)

(note: padding is 9 instead of 10 because of the hard-coded space between the words)

Answer 2

How about:

>>> column1 = ["soft","pregnant","tall"]
>>> column2 = ["skin","woman", "man"]
>>> for line in zip(column1, column2):
...     print '{:10}{}'.format(*line)
... 
soft      skin
pregnant  woman
tall      man

Answer 3

column1 = ["soft","pregnant","tall"]
column2 = ["skin","woman", "man"]

for row in zip(column1, column2):
    print "%-9s %s" % row # formatted to a width of 9 with one extra space after

Answer 4

Using Python 3

column1 = ["soft","pregnant","tall"]
column2 = ["skin","woman", "man"]

for line in zip(column1, column2):
    print('{:10}{}'.format(*line))

Answer 5

One liner using new style string formatting:

>>> column1 = ["soft", "pregnant", "tall"]
>>> column2 = ["skin", "woman", "man"]

>>> print "\n".join("{0}\t{1}".format(a, b) for a, b in zip(column1, column2))

soft        skin
pregnant    woman
tall        man