How to set a long Java classpath in Windows?

Question

I'm trying to run a particular JUnit test by hand on a Windows XP command line, which has an unusually high number of elements in the class path. I've tried several variations, such as:

set CLASS_PATH=C:\path\a\b\c;C:\path\e\f\g;....
set CLASS_PATH=%CLASS_PATH%;C:\path2\a\b\c;C:\path2\e\f\g;....
...
C:\apps\jdk1.6.0_07\bin\java.exe -client oracle.jdevimpl.junit.runner.TestRunner com.myco.myClass.MyTest testMethod

(Other variations are setting the classpath all on one line, setting the classpath via -classpath as an argument to java"). It always comes down to the console throwing up it's hands with this error:

The input line is too long.
The syntax of the command is incorrect.

This is a JUnit test testing a rather large existing legacy project, so no suggestions about rearranging my directory structure to something more reasonable, those types of solutions are out for now. I was just trying to gen up a quick test against this project and run it on the command line, and the console is stonewalling me. Help!

Answer 1

The Windows command line is very limiting in this regard. A workaround is to create a "pathing jar". This is a jar containing only a Manifest.mf file, whose Class-Path specifies the disk paths of your long list of jars, etc. Now just add this pathing jar to your command line classpath. This is usually more convenient than packaging the actual resources together.

As I recall, the disk paths can be relative to the pathing jar itself. So the Manifest.mf might look something like this:

Class-Path: this.jar that.jar ../lib/other.jar

If your pathing jar contains mainly foundational resources, then it won't change too frequently, but you will probably still want to generate it somewhere in your build. For example:

<jar destfile="pathing.jar">
  <manifest>
    <attribute name="Class-Path" value="this.jar that.jar ../lib/other.jar"/>
  </manifest>
</jar>

Answer 2

Since Java 6 you can use classpath wildcards .

Example: foo/* , refers to all .jar files in the directory foo

• this will not match class files (only jar files). To match both use: foo;foo/* or foo/*;foo . The order determines what is loaded first.
• The search is NOT recursive

Answer 3

Use An "Argument File" on Java 9+

In Java 9+, the java executable supports providing arguments via a file. See https://docs.oracle.com/javase/9/tools/java.htm#JSWOR-GUID-4856361B-8BFD-4964-AE84-121F5F6CF111 .

This mechanism is explicitly intended to solve the problem of OS limitations on command lengths:

You can shorten or simplify the java command by using @argument files to specify a text file that contains arguments, such as options and class names, passed to the java command. This let's you to create java commands of any length on any operating system.

In the command line, use the at sign (@) prefix to identify an argument file that contains java options and class names. When the java command encounters a file beginning with the at sign (@) , it expands the contents of that file into an argument list just as they would be specified on the command line.

This is the "right" solution, if you are running version 9 or above. This mechanism simply modifies how the argument is provided to the JVM, and is therefore 100% compatible with any framework or application , regardless of how they do classloading ie it is completely equivalent to simply providing the argument on the command line as usual. This is not true for manifest-based workarounds to this OS limitation.

An example of this is:

Original command:

java -cp c:\\foo\\bar.jar;c:\\foo\\baz.jar

can be rewritten as:

java @c:\\path\\to\\cparg

where c:\\path\\to\\cparg is a file which contains:

-cp c:\foo\bar.jar;c:\foo\baz.jar

This "argument file" also supports line continuation characters and quoting for properly handling spaces in paths eg

-cp "\
c:\foo\bar.jar;\
c:\foo\baz.jar"

Gradle

If you are encountering this issue in Gradle, see this plugin, which converts your classpath automatically into an "argument file" and provides that to the JVM when doing exec or test tasks on Windows. On Linux or other operating systems it does nothing by default, though an optional configuration value can be used to apply the transformation regardless of OS.

https://github.com/redocksoft/classpath-to-file-gradle-plugin

(disclaimer: I am the author)

See also this related Gradle issue -- hopefully this capability will eventually be integrated into Gradle core: https://github.com/gradle/gradle/issues/1989 .

Answer 4

(I suppose you do not really mean DOS, but refer to cmd.exe.)

I think it is less a CLASSPATH limitation than an environment size/environment variable size limit. On XP, individual environment variables can be 8k in size, the entire environment is limited to 64k. I can't see you would hit that limit.

There is a limit on windows that restricts the length of a command line, on WindowsNT+ it is 8k for cmd.exe. A set command is subject to that restriction. Can it be you have more than 8k worth of directories in your set command? You may be out of luck, then - even if you split them up like Nick Berardi suggested.

Answer 5

Thanks to Raman for introducing a new solution to a pathing problem for Java 9+. I made a hack to bootRun task that allows using everything already evaluated by gradle to run java with argument files. Not very elegant but working.

// Fix long path problem on Windows by utilizing java Command-Line Argument Files 
// https://docs.oracle.com/javase/9/tools/java.htm#JSWOR-GUID-4856361B-8BFD-4964-AE84-121F5F6CF111 
// The task creates the command-line argument file with classpath
// Then we specify the args parameter with path to command-line argument file and main class
// Then we clear classpath and main parameters
// As arguments are applied after applying classpath and main class last step 
// is done to cheat gradle plugin: we will skip classpath and main and manually
// apply them through args
// Hopefully at some point gradle will do this automatically 
// https://github.com/gradle/gradle/issues/1989 

if (Os.isFamily(Os.FAMILY_WINDOWS)) {
    bootRun {
        doFirst {
            def argumentFilePath = "build/javaArguments.txt"
            def argumentFile = project.file(argumentFilePath)
            def writer = argumentFile.newPrintWriter()
            writer.print('-cp ')
            writer.println(classpath.join(';'))
            writer.close()

            args = ["@${argumentFile.absolutePath}", main]
            classpath = project.files()
            main = ''
        }
    }
}

Answer 6

If I were in your shoes, I would download the junction utility from MS : http://technet.microsoft.com/en-us/sysinternals/bb896768.aspx and then map your "C:\\path" to say, "z:\\" and "c:\\path2" to say, "y:\\". This way, you will be reducing 4 characters per item in your classpath .

set CLASS_PATH=C:\path\a\b\c;C:\path\e\f\g;
set CLASS_PATH=%CLASS_PATH%;C:\path2\a\b\c;C:\path2\e\f\g;

Now, your classpath will be :

set CLASS_PATH=z\a\b\c;z\e\f\g;
set CLASS_PATH=%CLASS_PATH%;y:\a\b\c;y:\e\f\g;

It might do more depending on your actual classpath .

Answer 7

You could try this

---

@echo off
set A=D:\jdk1.6.0_23\bin
set B=C:\Documents and Settings\674205\Desktop\JavaProj
set PATH="%PATH%;%A%;"
set CLASSPATH="%CLASSPATH%;%B%;"

go to a command prompt and run it twice(no idea why....i have to do so on a windows XP machine) also the paths r set only for the current command prompt session

Answer 8

I think you are up the creek without a paddle here. The commandline has a limit for arguments to call a programm.

I have 2 sugestion you could try. First, prior to running the junit tests, you can let a script/ant_task create JARs of the various classes on the classpath. Then you can put the JARs on the classpath, which should be shorter.

Another way you could try is to create an antscript to run JUNIT, in ANT there should not be such a limit for classpath entries.

Answer 9

正如 HuibertGill 所提到的，我会将其包装在 Ant 构建脚本中，这样您就不必自己管理所有这些。

Answer 10

除了通过将 jar 文件移动到“C:\\jars”之类的文件夹中以某种方式缩短类路径之外，没有解决此问题的方法。

Answer 11

Fix for windows gradle long classpath issue. Fixes JavaExec tasks that error out with message "CreateProcess error=206, The filename or extension is too long"

Using the plugins DSL:

plugins {
  id "com.github.ManifestClasspath" version "0.1.0-RELEASE"
}

Using legacy plugin application:

buildscript {
  repositories {
    maven {
      url "https://plugins.gradle.org/m2/"
    }
  }
  dependencies {
    classpath "gradle.plugin.com.github.viswaramamoorthy:gradle-util-plugins:0.1.0-RELEASE"
  }
}

apply plugin: "com.github.ManifestClasspath"

Answer 12

I had a similar issue here with a giant classpath definition inside a .bat file. The problem was that this class path was also including the execution path into the giant path, its ok, its make sense. In this context, the software was not able to run and the message "The input line is too long" appeared everytime.

Solution: I just moved the all files to a shorter position. For instance, I was trying to execute the software in a directory tree like: c:\\softwares\\testing\\testing_solution\\one

and I moved the whole structure to a point like this

c:\\test

The software worked very well. It is not the best option, I know, but might help some one who is looking to a fast solution.

Tks

Answer 13

Have you tried stacking them?

set CLASS_PATH = c:\path
set ALT_A = %CLASS_PATH%\a\b\c;
set ALT_B = %CLASS_PATH%\e\f\g;
...

set ALL_PATHS = %CLASS_PATH%;%ALT_A%;%ALT_B%