I need to move the files of a directory to another directory.I get stat error when I used the following program.
for i in dir1/*.txt_dir; do
mv $i/*.txt dir2/`basename $i`.txt
done
error message
mv: cannot stat `dir1/aa7.txt_dir/*.txt': No such file or directory
Normally, when a glob which does not match any filenames is expanded, it remains unchanged. Thus, you get results like this:
$ rm .bak rm: cannot remove ` .bak': No such file or directory
To avoid this we need to change the default value of nullglob variable.
#BASH
shopt -s nullglob
for i in dir1/*.txt_dir; do
mv $i/*.txt dir2/'basename $i'.txt
done
Read more about it here: http://mywiki.wooledge.org/NullGlob
Hope this helps!
mv $i/*.txt dir2/`basename $i`.txt
This doesn't work when there are no text files in $i/
. The shell passes the raw string "$i/*.txt"
to mv
with the unexpanded *
in it, which mv
chokes on.
Try something like this:
for i in dir1/*.txt_dir; do
find $i -name '*.txt' -exec mv {} dir2/`basename $i`.txt \;
done
when you put directory/* alone in for iteration, it list each file with absolute path. use `ls
for i in ls dir1/*.txt_dir
; do
Whilst it is not shown in your example - using the correct quotes is important. in BASH "*" evaluates to * and '*' evaluates to the expansion glob. so
`ls *`
will show all files in directory and
`ls "*"`
will show all files named the literal *
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