简体繁体中英

writing an awk command to print every line that has at least one field

原文 2012-10-10 04:01:53 9 1 linux/ unix/ ubuntu

如何编写仅打印至少一个字段的行的awk命令

awk '{if (NF>0) print }'

1 answers

You command works, and prints lines with one or more fields. But awk prints by default, so you can simplify it:

awk 'NF > 0' file.txt

Print lines between two patterns through sed/AWK when there is at least one line between them

use awk to confront first number in every line of a file and print the whole line that contains the largest one

SED & AWK print entries in a file on one line

Why does my awk command print an extra line?

cut or awk command to print first field of first row

How to print a column using awk command line and add header

manipulate first field and then print rest of the line for csv files using awk

awk + print the field from line that defined with double quotes

AWK command print inversion

awk Print Line Issue

暂无

暂无

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

Related Question Print lines between two patterns through sed/AWK when there is at least one line between them use awk to confront first number in every line of a file and print the whole line that contains the largest one SED & AWK print entries in a file on one line Why does my awk command print an extra line? cut or awk command to print first field of first row How to print a column using awk command line and add header manipulate first field and then print rest of the line for csv files using awk awk + print the field from line that defined with double quotes AWK command print inversion awk Print Line Issue

Related Tags

粤ICP备18138465号 © 2020-2024 STACKOOM.COM