Bash for loop syntax error with pipe

Question

I'm trying this command

for x in qstat -u '*' | grep Eqw | awk {'print $1'}; do qmod -cj $x; done

and end up with this error:

-bash: syntax error near unexpected token `|'

I've tried wrapping my qstat command in various quotes and brackets to no avail, what am I doing wrong?

Answer 1

由于您似乎想遍历结果，因此将其更改为：

for x in `qstat -u '*' | grep Eqw | awk {'print $1'}`; do qmod -cj $x; done

Answer 2

An optimised version will be :

for x in $(qstat -u '*' | awk '/Eqw/{print $1}'); do qmod -cj "$x"; done

• the backquote (`) is used in the old-style command substitution. The foo=$(command) syntax is recommended instead. Backslash handling inside $() is less surprising, and $() is easier to nest. See http://mywiki.wooledge.org/BashFAQ/082
• awk can grep hitself

Answer 3

Use this sript instead:

for x in $(qstat -u * | awk '/Eqw/ {print $1}')
do
    qmod -cj $x
done

Answer 4

它应该是：

for x in $(qstat -u '*' | grep Eqw | awk '{print $1}'); do qmod -cj $x; done