How do i quit using a menu item in a python indicator application ?
menu = gtk.Menu()
buf = "Quit"
menu_items = gtk.MenuItem(buf) # click the Quit close the application. How to?
menu.append(menu_items)
menu_items.show()
ind.set_menu(menu)
gtk.main()
I would like to click the buf
menu item to close the application. def quit:
This worked for me, import sys at top.
import sys
Then in the function that you want to quit put in:
sys.exit(0)
My working example below (check quitApplicaiton function):
#!/usr/bin/env python
#
#
# Authors: Stuart Page <xxx@gmail.com>
#
#
import gobject
import gtk
import appindicator
import sys
def menuitem_response(w, optionName):
print optionName
def quitApplication(w, optionName):
sys.exit(0)
if __name__ == "__main__":
ind = appindicator.Indicator ("example-simple-client",
"indicator-messages",
appindicator.CATEGORY_APPLICATION_STATUS)
ind.set_status (appindicator.STATUS_ACTIVE)
ind.set_attention_icon ("indicator-messages-new")
# create a menu
menu = gtk.Menu()
# create some drop down options
optionName = "Menu Option - 1"
menu_items = gtk.MenuItem(optionName)
menu.append(menu_items)
menu_items.connect("activate", menuitem_response, optionName)
menu_items.show()
optionName = "Menu Option - 2"
menu_items = gtk.MenuItem(optionName)
menu.append(menu_items)
menu_items.connect("activate", menuitem_response, optionName)
menu_items.show()
optionName = "Quit"
menu_items = gtk.MenuItem(optionName)
menu.append(menu_items)
menu_items.connect("activate", quitApplication, optionName)
menu_items.show()
ind.set_menu(menu)
gtk.main()
There are several ways to implement this function
import sys
def quit(widget):
sys.exit(0)
import os
def quit(widget):
os.kill(os.getpid(), 9)
def quit(widget):
gtk.main_quit()
then, you should connect your callback to menu item when click(activate) it, like following:
menu = gtk.Menu()
item = gtk.MenuItem("quit")
item.connect("activate", quit)
item.show()
menu.append(item)
while, i prefer the 3th method to define quit, It is the fastest as i test!
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