Node position in xml - Java

Question

I would like to prepare function which will give me position of node in xml.
For example:

int NodePosition = doc.getDocumentElement().getChildNodes().item(t).getNodeName().Position()

and in future I would like make some like this (of course this is example):

System.out.println(Node.row[NodePosition].tostring());

Is it possible to make something like this? Or maybe you know some function which make something like this.

For example when I go deeper there is a problem to get position. Because m = 7

doc.getDocumentElement().getChildNodes().item(t).getChildNodes().item(m)

When I try make this (but I have to save position):

System.out.println(doc.getDocumentElement().getChildNodes().item(7).getNodeName());

I get error

java.lang.NullPointerException

Answer 1

To me it looks like you are reinventing the wheel - you are trying to build your own version of XPath - See: http://www.ibm.com/developerworks/library/x-javaxpathapi/index.html