Fill array dynamically PHP

Question

I want to fill an array with the links that I get from this foreach. How can I do that?

foreach($html->find('a') as $link) {
       echo $link->href; //output: link1.html link2.html link3.html......
}

Answer 1

所有你需要的是

$links = array_map(function($v){return $v->href;}, $html->find('a'));

Answer 2

I'd say array_map() is the best way:

$links = array_map(function($link) { return $link->href; }, $html->find('a'));

It takes everything in the given array (in this case, $html->find('a') ) and returns a new array based on a map using the function you give it (in this case, function($link) { return $link->href; } ). It applies that function to each element in the given array to create each element in the returned array.

Answer 3

With array_push . See this link

<?php
$stack = array();
foreach($html->find('a') as $link) {
   array_push($stack, $link->href); 
}
print_r($stack);
?>

Answer 4

It's simple, Try this :-

$dataArray = array();
foreach($html->find('a') as $link) {
       $dataArray[] = $link->href; 
}

echo '<pre>';
print_r($dataArray);
 echo '</pre>';

Answer 5

把它放在循环中：$ links [] = $ link-> href;

Answer 6

$hrefs=array();
foreach($html->find('a') as $link) {
       $hrefs[]= $link->href; //output: link1.html link2.html link3.html......
}

That should do it.