How do I print this returned value in php?

Question

function printmsg($string,$type) {//type 1 = green, type 2 = red
    if($type == 1) $msg = "<p style=\"color:#00C5CD\">".$string."</p>";
    if($type == 2) $msg = "<p style=\"color:#f7110b\">".$string."</p>";
    return $msg;
}
printmsg("hello",1);

//lots of other code
print($msg);

Im trying to get my returned value to print but it never seems to work.

Answer 1

How about saving the return of the function in a variable and printing the variable

function printmsg($string,$type) {//type 1 = green, type 2 = red
    if($type == 1) $msg = "<p style=\"color:#00C5CD\">".$string."</p>";
    if($type == 2) $msg = "<p style=\"color:#f7110b\">".$string."</p>";
    return $msg;
}
$msg = printmsg("hello",1);

//lots of other code
print($msg);

Answer 2

if you are returning something you must have to catch it in some variables. Also in PHP you need to use echo to print the variables.

function printmsg($string,$type) {//type 1 = green, type 2 = red
    if($type == 1) $msg = "<p style=\"color:#00C5CD\">".$string."</p>";
    if($type == 2) $msg = "<p style=\"color:#f7110b\">".$string."</p>";
    return $msg;
}
$msg = printmsg("hello",1);

//lots of other code
echo $msg;

Answer 3

Just echo it

function printmsg($string,$type) {//type 1 = green, type 2 = red
    if($type == 1) $msg = "<p style=\"color:#00C5CD\">".$string."</p>";
    if($type == 2) $msg = "<p style=\"color:#f7110b\">".$string."</p>";
    return $msg;
}
echo printmsg("hello",1);

Answer 4

You want this:

function printmsg($string,$type) {//type 1 = green, type 2 = red
if($type == 1) $msg = "<p style=\"color:#00C5CD\">".$string."</p>";
if($type == 2) $msg = "<p style=\"color:#f7110b\">".$string."</p>";
return $msg;

} $msg=printmsg("hello",1);

//lots of other code print($msg);