I need a regex with extract me a number which is always at the end of a file wrapped in ().
For example:
Vacation (1).png returns 1
Vacation (Me and Mom) (2).png returns 2
Vacation (5) (3).png returns 3
Hope some regex pros are out there :)
This should do it ( demo on ideone.com ):
preg_match( '/^.*\((\d+)\)/s', $filename, $matches );
$number = $matches[1];
The greedy ^.*
causes the regexp to first match as many characters as possible, and then to backtrack until it can match \\((\\d+)\\)
, ie a number surrounded by parentheses.
Just write it, $
is the end of the subject:
$pattern = '/\((\d+)\)\.png$/';
$number = preg_match($pattern, $subject, $matches) ? $matches[1] : NULL;
This is a so called anchored pattern, it works very well because the regular expression engine knows where to start - here at the end.
The rest in this crazy pattern is just quoting all the characters that need quoting:
(, ) and . => \(, \) and \. in:
().png => \(\)\.png
And then a group for matches is put in there to only contain one or more ( +
) digits \\d
:
\((\d+)\)\.png
^^^^^
Finally to have this working, add the $
to mark the end:
\((\d+)\)\.png$
^
Ready to run.
Keep it simple. Use preg_match_all
preg_match_all('/\((\d+)\)/', $filename, $m);
$num=end(end($m));
<?php
$pattern = '/(.+)\((\d+)\)\.png/';
$test1 = "Vacation LDJFDF(1).png";
$test2 = "Vacation (Me and Mom) (2).png";
$test3 = "Vacation (5)(3).png";
preg_match($pattern, $test1, $matches);
print $matches[2];
print "\n";
preg_match($pattern, $test2, $matches);
print $matches[2];
print "\n";
preg_match($pattern, $test3, $matches);
print $matches[2];
print "\n";
?>
php test.php 1 2 3
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