An user has more tasks, 1 : N connection.
Visually:
admin
task1 2011/01/01 00:00:01
task2 2011/01/01 00:00:04
task3 2011/01/01 00:00:02
user2
task1 2011/03/01 00:01:01
task2 2011/03/01 00:01:04
task3 2011/03/01 00:01:02
(see the schema from my previous question )
How to left join the user and the last "task", not get all of them?
The matter is I dont know how to do it with pure SQL... I saw some example here, but they are not working.
If we consider that you have the user id inside $user_id
and according to your schema in a previous question , you can try this:
$q = Doctrine_Query::create()
->select('u.*, t.*')
->from('User u')
->leftJoin('u.Task t')
->where('t.id IN (SELECT t2.id FROM Task t2 WHERE t2.owner_id = ? ORDER BY t2.id DESC LIMIT 1)', array($user_id));
$res = $q->execute();
Here is the documentation for subqueries in Doctrine.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.