I have a windows form that, on the click of a button, runs a process (MATLAB) and executes a file.
Dim myProcesses() As Process
myProcesses = Process.GetProcessesByName("Matlab")
If myProcesses.Count > 0 Then
'~~~~ what goes here? ~~~~
Else
Dim startInfo As New ProcessStartInfo
startInfo.FileName = "C:\Program Files\MATLAB\R2011b\bin\matlab.exe"
startInfo.WorkingDirectory = MatlabDir 'MatlabDir is defined elsewhere
startInfo.Arguments = "matlab.exe -r test_plot2"
Process.Start(startInfo)
End If
The above code opens MATLAB and executes the script "test_plot2.m" if MATLAB isn't already open. But what do I write in the first IF statement, if MATLAB is already open, and all I want to do is run the file?
Thanks in advance.
Its supposed to be the same. I mean, it doesn't matter if its opened or not, unless the application (Matlab) manages something different, then you have to guess how. Have you tried just using the same code?
Example:
Dim startInfo As New ProcessStartInfo
startInfo.FileName = "notepad.exe"
startInfo.Arguments = "C:\temp\test.txt"
Process.Start(startInfo)
It doesn't matter if you have Notepad already opened or not.
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