I need to invoke different functionality if we pass file name and file path
ex
python test.py test1 (invoke different function)
python test.py /home/sai/test1 (invoke different function)
I can get the argument from sys.argv[1]. But I am not able to differentiate into file and filepath.(ie is it file or file path)
It's a tricky bit as a name of the file is also a valid relative path, right? You can not differentiate it.
On the other hand assuming you would like to differentiate an absolute path or a relative path starting with a slash\\backslash you could use os.path.isabs(path) . Doc says it checks if the path starts with slash on Unix, backlash on Win after chopping a potential drive letter:
>>> import os
>>> os.path.isabs('C:\\folder\\name.txt')
True
>>> os.path.isabs('\\folder\\name.txt')
True
>>> os.path.isabs('name.txt')
False
However this will fail with a relative path not beginint with slash:
>>> os.path.isabs('folder\\name.txt')
False
The solution that would work with all cases mentioned above, not sensitive to relative paths with slashes or without them, would be to perform a comparison of the tail of path with the path itself using os.path.basename(path) . If they are equal it's just a name:
>>> os.path.basename('C:\\folder\\name.txt') == 'C:\\folder\\name.txt'
False
>>> os.path.basename('\\folder\\name.txt') == '\\folder\\name.txt'
False
>>> os.path.basename('folder\\name.txt') == 'folder\\name.txt'
False
>>> os.path.basename('name.txt') == 'name.txt'
True
Did you try
os.path.basename
or
os.path.dirname
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