简体   繁体   中英

MySQL query select DISTINCT but display all rows

I need help with DISTINCT . I would like to display Distinct row but display also all rows

Example this table from database:

+----+-----+-----+
|col1|col2 |col3 |
+----+-----+-----+
|A   |one  |two  |
|A   |three|four |
|A   |five |six  |
|B   |seven|eight|
|B   |nine |ten  |
+----+-----+-----+

I would like the display to look like this :

A
one  |two
three|four
five |six

B
seven|eight
nine |ten

Can anyone help?

The easiest way would be to fetch all rows from the database, and then group them in PHP.

// Querying:
$query = mysql_query('select * from tbl');
$results = array(); // Store all results in an array, grouped by col1

while($row = mysql_fetch_assoc($query)) {
    $col1 = $row['col1'];

    // This is basically grouping your rows by col1
    if(!isset($results[$col1]))
        $results[$col1] = array();
    $results[$col1][] = $row;
}

// Displaying:
foreach($results as $col1 => $rows) {
    echo "<h1>" . $col1 . "</h1>";

    foreach($rows as $row) {
        echo $row['col2'] . "|" . $row['col3'] . "<br />";
    }
}

Yields:

<h1>A</h1>
one  |two
three|four
five |six

<h1>B</h1>
seven|eight
nine |ten

Note that I use the deprecated mysql_functions just for simplicity, do not use them in production.

Here is how you can do it

$query="select 
            distinct    (col1) as col1,
            GROUP_CONCAT(col2) as col2,
            GROUP_CONCAT(col3) as col3
        FROM test
        group by col1";
$query = mysql_query($query);

This will fetch this output

col1    col2            col3 
A       one,three,five  two,four,six 
B       seven,nine      eight,ten 

while($row = mysql_fetch_assoc($query)) 
{
    $col1 = $row['col1'];
    $col2   =   explode(',',$row['col2']);
    $col3   =   explode(',',$row['col3']);

    for($i=0;$i<=count($col2);$i++)
    {
        $value  =   '';
        if(isset($col2[$i])){
            $value  =   $col2[$i];
            $value  .=  ' | ';
        }
        if(isset($col3[$i])){
        $value  .=  $col3[$i];
        }
            echo $value; 
    }
}

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM