坚持使用Java程序（java.io. *;）？

Question

我程序的目的是询问温度（F）是多少，以及外面的天气情况如何。

天气条件可以是晴天（1），下雨（2），多云（3）或下雪（4.）数字1-4将用于阐明天气条件（我不确定该怎么做还有其他方法...）

然后，根据temp和weatherCondition的组合，我希望能够根据temp和weatherCondition的组合显示10种选择中的3件衣服。

我仍在学习，因此如果我的问题似乎很平凡，我深表歉意...

当用户输入temp和weatherCondition ，将根据两个输入的组合（例如，热晴天， weatherCondition ）给出响应。

相反，我想创建一个或多个txt文件，并让每个文件都命名为hotSunny.txt 。 在这些txt文件中，我列出了10种服装。 我最终希望程序识别出哪个组合匹配其适当的txt文件，然后随机显示10个中的3个。

我到目前为止所拥有的...

   public static void main(String[] args)
   {
      double temperature;    
      int weatherCondition;  
      String input;          


      input = JOptionPane.showInputDialog("What is " +
                                "the current temperature?");
      temperature = Double.parseDouble(input);


      input = JOptionPane.showInputDialog("Sweet I now know the temperature! " +
             "Now please take a look out the nearest window is it Sunny , Rainy ," +
             " Cloudy or Snowy? " +
             "(1 = Sunny) (2 = Raining) " +
             "(3 = Cloudy) (4 = Snowing)");


      weatherCondition = Integer.parseInt(input);


      if (temperature <= 32){
          if (weatherCondition == 4){
              freezingSnowing();
          } else if (weatherCondition == 3){
              freezingCloudy();
          } else if (weatherCondition == 2){
              freezingRain();
          } else {
              freezingSunny();
          }
    }..........
      else if ((temperature >= 33) && (temperature <= 50)) {

      else if ((temperature >= 51) && (temperature <= 75)) {

      else if ((temperature >= 76) && (temperature <= 140)) {

public static void freezingSnowing()       
{
   JOptionPane.showMessageDialog(null, "It's is snowing! I recommend that you dress very warm" +
                         "and wear a large coat that is preferably water proof.");
} 

Answer 1

您的freezingSnowing方法应如下所示：

public static void freezingSnowing() {
    file = new File(MyWeatherApp.class.getResource
                                (path + "freezingSnowing.txt"));
                   // path to the txt file
                   // where path is the local path to the file
    scanner = new Scanner(file);

    ArrayList<String> garments = new ArrayList<>(10);
    while(scanner.hasNextLine()) {
        garments.add(scanner.nextLine());
    }

    ArrayList<Integer> indices = new ArrayList<>(3);
    for(int i = 0; i < 3; i++) {
        while(true) { // watch out for duplicates
           int rand = (int)(Math.random() * 9);
           if(!indices.contains(rand))
               break;
        }
        indices.add(rand);

    JOptionPane.showMessageDialog(null, "It's is snowing! " +
                "I recommend that you dress very warm " +
                "and wear " + garments.get(indices.get(1)) +
                ", " garments.get(indices.get(2)) +
                " and " + garments.get(indices.get(3)) +
                ".");
}

Answer 2

这是我的随机选择项目版本。

public static void main(String[] args) {
    String[] weatherCond = new String[] {"cold", "hot"};
    ArrayList<String> garmets = new ArrayList<String>();
    garmets.add("clothes");
    garmets.add("hat");
    garmets.add("gloves");
    garmets.add("coat");
    ArrayList<String> pick;
    int ITEM = 3;

    int temperature = 29;

    if (temperature >= 30) {  // hot condition
        System.out.println("weather condition " + weatherCond[0]);
        pick = garmets;
        for (int i = 0; i < ITEM; i++) {
            int idx = (int) (Math.round(Math.random() * pick.size()) % pick.size());        
            System.out.print(pick.get(idx) + " " );
            pick.remove(idx);
        }
    } else {
        System.out.println("weather condition " + weatherCond[1]);
        pick = garmets;
        for (int i = 0; i < ITEM; i++) {
            int idx = (int) (Math.round(Math.random() * pick.size()) % pick.size());        
            System.out.print(pick.get(idx) + " " );
            pick.remove(idx);
        }
    }
}

另外，如果你想使用一个固定组garmets的特定气候条件下，你可以使用它使用的天气状况作为重点和garmet组作为值HashMap中 。