坚持使用Java程序（java.io. *;）？

Question

The purpose of my program is to ask what the temperature(F) is and what the weather condition outside is like.

The weather condition can be either sunny(1), raining(2), cloudy(3) or snowing(4.) The numbers 1-4 will be used to clarify what the weather condition is (I'm not sure how to do it any other way...)

Then, depending on the combination of temp and weatherCondition I want to be able to display 3 garments out of 10 choices, based on the combo of temp and weatherCondition .

I'm still learning so I apologize if my question or problem seems mundane...

At the moment when a user enters the temp and weatherCondition , a response is given depending on the combo of the two inputs (ex. hot-sunny, freezing-snowing).

Instead, I would like to create one or more txt files and have each one named something like hotSunny.txt for example. Inside these txt files I've listed 10 types of garments. I ultimately want the program to recognize which combo matches its appropriate txt file and then randomly display 3 of the 10.

What I've got so far...

   public static void main(String[] args)
   {
      double temperature;    
      int weatherCondition;  
      String input;          


      input = JOptionPane.showInputDialog("What is " +
                                "the current temperature?");
      temperature = Double.parseDouble(input);


      input = JOptionPane.showInputDialog("Sweet I now know the temperature! " +
             "Now please take a look out the nearest window is it Sunny , Rainy ," +
             " Cloudy or Snowy? " +
             "(1 = Sunny) (2 = Raining) " +
             "(3 = Cloudy) (4 = Snowing)");


      weatherCondition = Integer.parseInt(input);


      if (temperature <= 32){
          if (weatherCondition == 4){
              freezingSnowing();
          } else if (weatherCondition == 3){
              freezingCloudy();
          } else if (weatherCondition == 2){
              freezingRain();
          } else {
              freezingSunny();
          }
    }..........
      else if ((temperature >= 33) && (temperature <= 50)) {

      else if ((temperature >= 51) && (temperature <= 75)) {

      else if ((temperature >= 76) && (temperature <= 140)) {

public static void freezingSnowing()       
{
   JOptionPane.showMessageDialog(null, "It's is snowing! I recommend that you dress very warm" +
                         "and wear a large coat that is preferably water proof.");
} 

Answer 1

Your freezingSnowing method should look like this:

public static void freezingSnowing() {
    file = new File(MyWeatherApp.class.getResource
                                (path + "freezingSnowing.txt"));
                   // path to the txt file
                   // where path is the local path to the file
    scanner = new Scanner(file);

    ArrayList<String> garments = new ArrayList<>(10);
    while(scanner.hasNextLine()) {
        garments.add(scanner.nextLine());
    }

    ArrayList<Integer> indices = new ArrayList<>(3);
    for(int i = 0; i < 3; i++) {
        while(true) { // watch out for duplicates
           int rand = (int)(Math.random() * 9);
           if(!indices.contains(rand))
               break;
        }
        indices.add(rand);

    JOptionPane.showMessageDialog(null, "It's is snowing! " +
                "I recommend that you dress very warm " +
                "and wear " + garments.get(indices.get(1)) +
                ", " garments.get(indices.get(2)) +
                " and " + garments.get(indices.get(3)) +
                ".");
}

Answer 2

This is my version of randomly picking item.

public static void main(String[] args) {
    String[] weatherCond = new String[] {"cold", "hot"};
    ArrayList<String> garmets = new ArrayList<String>();
    garmets.add("clothes");
    garmets.add("hat");
    garmets.add("gloves");
    garmets.add("coat");
    ArrayList<String> pick;
    int ITEM = 3;

    int temperature = 29;

    if (temperature >= 30) {  // hot condition
        System.out.println("weather condition " + weatherCond[0]);
        pick = garmets;
        for (int i = 0; i < ITEM; i++) {
            int idx = (int) (Math.round(Math.random() * pick.size()) % pick.size());        
            System.out.print(pick.get(idx) + " " );
            pick.remove(idx);
        }
    } else {
        System.out.println("weather condition " + weatherCond[1]);
        pick = garmets;
        for (int i = 0; i < ITEM; i++) {
            int idx = (int) (Math.round(Math.random() * pick.size()) % pick.size());        
            System.out.print(pick.get(idx) + " " );
            pick.remove(idx);
        }
    }
}

Also, if you want to use a fix set of garmets for a specific weather condition, you could use a hashmap which uses weather condition as a key and garmet groups as a value.