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如何在unittest Python中创建继承的类的实例,以便我可以在simpleXMLRPCServer中注册该类的实例

[英]How to create an instance of an inherited class in unittest Python so that I can register the instance of that class in simpleXMLRPCServer

from __future__ import with_statement
from sikuli.Sikuli import *

import os
import unittest
import this
import xmlrpclib
import SimpleXMLRPCServer, SocketServer, threading

class SimpleThreadedXMLRPCServer(SocketServer.ThreadingMixIn, SimpleXMLRPCServer.SimpleXMLRPCServer):
    pass

class ABC(object):
    def A(self):
      ...........
    def B(self):
      ...........
    def C(self):
      ...........     


class XYZ(unittest.TestCase,ABC):
    def setUp(self):
         print "Inside setup"
         pass      
    def tearDown(self):
         print "Inside tearDown" 
         pass
    def test_1(self):
        self.A()
        self.B()
        self.C()


    def D(self):    
        print "Inside D"
        return True    


suite = unittest.TestLoader().loadTestsFromTestCase(XYZ)

class ServerThread(threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)
        self.server = SimpleThreadedXMLRPCServer(("x.x.x.1", 8000))
        #self.server.register_instance() #How to Register an instance of XYZ here.
    def run(self):
        self.server.serve_forever()

server = ServerThread()
server.start()

所以我的问题是如何在这里注册XYZ实例。 在上面的注释行中,因此可以从XMLRPC客户端调用它,例如:

client = xmlrpclib.ServerProxy("http://x.x.x.2:8000")
handraise = client.D() #Or any other possible way

我知道它可以与register_function(D)一起工作,但我希望使用register_instance()公开整个XYZ类。

从理论上讲,这应该起作用:

self.server.register_instance(XYZ())    # but it throwed some runTest Error for me

无论如何,在register_instance内的Classname中显式地将方法名称作为arg传递:

self.server.register_instance(XYZ("D"))

符合我的预期。
然后从xmlrpc客户端调用D(),如下所示:

handraise = client.D()

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