from __future__ import with_statement
from sikuli.Sikuli import *
import os
import unittest
import this
import xmlrpclib
import SimpleXMLRPCServer, SocketServer, threading
class SimpleThreadedXMLRPCServer(SocketServer.ThreadingMixIn, SimpleXMLRPCServer.SimpleXMLRPCServer):
pass
class ABC(object):
def A(self):
...........
def B(self):
...........
def C(self):
...........
class XYZ(unittest.TestCase,ABC):
def setUp(self):
print "Inside setup"
pass
def tearDown(self):
print "Inside tearDown"
pass
def test_1(self):
self.A()
self.B()
self.C()
def D(self):
print "Inside D"
return True
suite = unittest.TestLoader().loadTestsFromTestCase(XYZ)
class ServerThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.server = SimpleThreadedXMLRPCServer(("x.x.x.1", 8000))
#self.server.register_instance() #How to Register an instance of XYZ here.
def run(self):
self.server.serve_forever()
server = ServerThread()
server.start()
So my question is that how to Register an instance of XYZ
here. In the commented line above so that it can be called from the XMLRPC client like:
client = xmlrpclib.ServerProxy("http://x.x.x.2:8000")
handraise = client.D() #Or any other possible way
I know it works with register_function(D)
but I want the whole class XYZ
to be exposed using register_instance()
.
Theoretically this should work:
self.server.register_instance(XYZ()) # but it throwed some runTest Error for me
Anyways, passing the method name explicitly as an arg in the Classname inside register_instance like:
self.server.register_instance(XYZ("D"))
worked as expected for me.
And from the xmlrpc client, call the D() like:
handraise = client.D()
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