[英]Codeigniter - Array dont work correctly
每当我调用此函数时,我都会正确获取user_id,但未检查密码...
模型:
<?php
class Prometheus_model extends CI_Model {
var $tables = array(
'bots' => 'bots',
'users' => 'users'
);
function __construct() {
parent::__construct();
}
public function tablename($table = NULL) {
if(! isset($table)) return FALSE;
return $this->tables[$table];
}
public function get($table, $where = array(), $order = NULL) {
$this->db->where($where);
if(isset($order)) {
$this->db->order_by($order);
}
$q = $this->db->get_where($this->tablename($table),$where);
$result = $q->result_array();
// You should use $q->num_rows() to detect the number of returned rows
if($q->num_rows()) {
return $result[0];
}
return $result;
}
public function update($table, $where = array(), $data) {
$this->db->update($this->tablename($table),$data,$where);
return $this->db->affected_rows();
}
public function insert($table, $data) {
$this->db->insert($this->tablename($table),$data);
return $this->db->insert_id();
}
public function delete($table, $where = array()) {
$this->db->delete($this->tablename($table),$where);
return $this->db->affected_rows();
}
public function explicit($query) {
$q = $this->db->query($query);
if(is_object($q)) {
return $q->result_array();
} else {
return $q;
}
}
public function num_rows($table, $where = NULL) {
if(isset($where)){
$this->db->where($where);
}
$q = $this->db->get($table);
return $q->num_rows();
}
public function get_bot_data_by_hw_id($bot_hw_id) {
$q = $this->get('bots', array('bot_hw_id' => $bot_hw_id));
return $q;
}
public function check_user_data($user_incredials, $user_password) {
if($this->num_rows('users', array('user_name' => $user_incredials, 'user_password' => $this->encrypt->decode($user_password))) == 1){
$q = $this->get('users', array('user_name' => $this->security->xss_clean($user_incredials)));
return $q['user_id'];
}
return FALSE;
}
}
?>
我在控制器上的函数调用:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Login extends CI_Controller {
public function index(){
if($this->input->post('user_login')){
var_dump($this->prometheus_model->check_user_data($this->input->post('user_incredials'), $this->input->post('user_password')));
}
$this->load->view('login_index');
}
}
我该如何解决?
在您的check_user_data()
方法中,您正在使用
if($this->num_rows('users', array('user_name' => $user_incredials, 'user_password' => $this->encrypt->decode($user_password))) == 1)
我认为(逻辑上)以下代码
$this->encrypt->decode($user_password)
应该
$this->encrypt->encode($user_password)
因为,您正在调用num_rows()
方法,它是
public function num_rows($table, $where = NULL)
{
if(isset($where)){
$this->db->where($where);
}
$q = $this->db->get($table);
return $q->num_rows();
}
实际上是在查询数据库,例如
select * from USERS where user_name = 'heera' and password = decode('abcde12345')
在这种情况下,您需要使用encode
(而非解码)方法encode
您尝试匹配的密码进行加密,因为用户给了您一个非加密(普通)密码,并且保存在数据库中的密码已经加密,因此在查询数据库以使其与已编码的密码匹配之前,请使用encode
方法对普通密码进行encode
。
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