[英]sqlalchemy AND operator from dict
我得到这种奇怪的行为
test_dict = {'productDue' : ['foo'],'releaseDue' : ['bar']}
for attr, value in test_dict.items() :
print attr
and_args = [(and_(getattr(my_table,attr).in_(value)))]
这给了我:
>>> print and_(*and_args)
"my_table"."releaseDue" IN (:releaseDue_1)
然后,当我切换顺序时:
test_dict = {'releaseDue' : ['bar'],'productDue' : ['foo']}
for attr, value in test_dict.items() :
print attr
and_args = [(and_(getattr(my_table,attr).in_(value)))]
我得到:
>>> print and_(*and_args)
"TDC"."releaseDue" IN (:releaseDue_1)
我不明白,我想拥有"TDC"."releaseDue" IN (:releaseDue_1) AND "TDC"."productDue" IN (:productDue_1)
请帮助
谢谢,
我已经做到了:
and_args = [ (and_(getattr(my_table,attr).in_(value))) for attr, value in test_dict.items() ]
我不是sqlalchemy专家,但这难道是因为您每次循环都要覆盖and_args吗?
做类似的事情
test_dict = {'productDue' : ['foo'],'releaseDue' : ['bar']}
and_args = []
for attr, value in test_dict.items() :
print attr
and_args.append( and_(getattr(my_table,attr).in_(value) )
all = and_(*and_args)
绝招?
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