[英]Parsing a string for data sets
我有一个长字符串,其中包含需要分开/提取以进行评估的信息集。
作为一个初学者程序员,我知道各种解析操作,例如split()append()remove()等-但我正在努力提出一种将它们组合以提取相关数据的逻辑方法...
长串...
"<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>"
包含3组数据需要存储为浮点值
[Set1] s = 1 e = 2176 t = -20774 r = 1
[Set2] s = 2177 e = 8982 t = -18597 r = 1
[Set3] s = 8983 e = 10393 t = -150.2 r = 1
我希望将每组数据存储为一个列表
Set1 = [1,2176,-20774,1]
Set2 = [2177,8982,-18597,1]
Set3 = [2178,10393,-150.2,1]
注意:套数可以变化
使用内置的ElementTree库从xml中提取数据:
import xml.etree.ElementTree as ET
data = '<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>'
tree = ET.fromstring(data)
for b in tree.findall('.//B'):
print map(float, itemgetter(*'setr')(b.attrib))
印刷品:
[1.0, 2176.0, -20774.0, 1.0]
[2177.0, 8982.0, -18597.0, 1.0]
[8983.0, 10393.0, -150.22, 1.0]
注意:这是先前答案的扩展...
(@alecxe和@Jon Clements的道具)
为了标记每个数据集并以易于访问的格式存储结果
import xml.etree.ElementTree as ET
import operator
data = '<Sets X="s"><B s="1" e="2176" t="-2.0774E4" r="1" /><B s="2177" e="8982" t="-1.8597E4" r="1" /><B s="8983" e="10393" t="-150.22" r="1" /></Sets>'
dataDictionary = {}
tree = ET.fromstring(data)
setNumber = 0
for b in tree.findall('.//B'):
setNumber = setNumber + 1
dataSet = map(float, operator.itemgetter(*'setr')(b.attrib))
dataDictionary[setNumber] = dataSet
print "This is dataset " +str(setNumber)
print dataSet
print ""
print "This is the Dictionary of datasets"
print dataDictionary
这将导致以下输出-易于将来操作使用:)
This is dataSet 1
[1.0, 2176.0, -20774.0, 1.0]
This is dataSet 2
[2177.0, 8982.0, -18597.0, 1.0]
This is dataSet 3
[8983.0, 10393.0, -150.22, 1.0]
This is the dataDictionary
{1: [1.0, 2176.0, -20774.0, 1.0], 2: [2177.0, 8982.0, -18597.0, 1.0], 3: [8983.0, 10393.0, -150.22, 1.0]}
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