[英]How to compare two dictionary
我有两个字典,我想比较一下
实际上字典结构就像Facebook的兴趣列表,如下
我想找出我和朋友之间的共同兴趣
我检索了两个用户的兴趣列表,但是当我比较兴趣字典时,因为created_time不同,所以我没有得到通用字典
category = "Musical instrument";
"created_time" = "2011-06-11T09:10:07+0000";
id = 113099055370169;
name = Guitar;
和
category = "Musical instrument";
"created_time" = "2013-09-27T06:02:28+0000";
id = 113099055370169;
name = Guitar;
任何人都可以建议任何有效的方法来做到这一点
现在我正在使用,但它并没有给我带来共同的利益,因为
for (int count = 0; count < [arrFriendsInterest count]; count++)
{
NSDictionary *dictFriend = [arrFriendsInterest objectAtIndex:count];
if ([arrMyIntrest containsObject:dictFriend]) {
[arrMutualInterest addObject:dictFriend];
}
}
其中arrFriendsInterest是包含朋友兴趣的字典数组
而arrMyIntrest是包含我的兴趣的字典数组×注释只能被编辑5分钟×注释只能被编辑5分钟×注释只能被编辑5分钟
首先,您将数据存储在NSArray中吗?
如果是,那么请更轻松地使用以下代码。
// Do any additional setup after loading the view, typically from a nib.
NSArray *ar1 = [NSArray arrayWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:@"Musical instrument",@"category",@"2011-06-11T09:10:07+0000",@"created_time",@"113099055370169",@"id", @"Guitar",@"name", nil], nil];
NSArray *ar2 = [NSArray arrayWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:@"Musical instrument",@"category",@"2013-09-27T06:02:28+0000",@"created_time",@"113099055370169",@"id", @"Guitar",@"name", nil], nil];
NSMutableSet* set1 = [NSMutableSet setWithArray:ar1];
NSMutableSet* set2 = [NSMutableSet setWithArray:ar2];
[set1 unionSet:set2]; //this will give you only the obejcts that are in both sets
NSArray* result = [set1 allObjects];
NSLog(@"%@",[result mutableCopy]);
快乐编码!!!
假设您只需要比较“ id”值:
NSArray* myIds = [arrMyInterest valueForKey:@"id"];
for (int count = 0; count < [arrFriendsInterest count]; count++) {
NSDictionary *dictFriend = [arrFriendsInterest objectAtIndex:count];
// Not clear whether "id" is NSString or NSNumber -- use whichever
NSString* friendId = [dictFriend valueForKey:@"id"];
if ([myIds containsObject:friendId]) {
[arrMutualInterest addObject:dictFriend];
}
}
为什么不使用自定义类而不是使用NSDictionary?
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