[英]How to compare two dictionary
我有兩個字典,我想比較一下
實際上字典結構就像Facebook的興趣列表,如下
我想找出我和朋友之間的共同興趣
我檢索了兩個用戶的興趣列表,但是當我比較興趣字典時,因為created_time不同,所以我沒有得到通用字典
category = "Musical instrument";
"created_time" = "2011-06-11T09:10:07+0000";
id = 113099055370169;
name = Guitar;
和
category = "Musical instrument";
"created_time" = "2013-09-27T06:02:28+0000";
id = 113099055370169;
name = Guitar;
任何人都可以建議任何有效的方法來做到這一點
現在我正在使用,但它並沒有給我帶來共同的利益,因為
for (int count = 0; count < [arrFriendsInterest count]; count++)
{
NSDictionary *dictFriend = [arrFriendsInterest objectAtIndex:count];
if ([arrMyIntrest containsObject:dictFriend]) {
[arrMutualInterest addObject:dictFriend];
}
}
其中arrFriendsInterest是包含朋友興趣的字典數組
而arrMyIntrest是包含我的興趣的字典數組×注釋只能被編輯5分鍾×注釋只能被編輯5分鍾×注釋只能被編輯5分鍾
首先,您將數據存儲在NSArray中嗎?
如果是,那么請更輕松地使用以下代碼。
// Do any additional setup after loading the view, typically from a nib.
NSArray *ar1 = [NSArray arrayWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:@"Musical instrument",@"category",@"2011-06-11T09:10:07+0000",@"created_time",@"113099055370169",@"id", @"Guitar",@"name", nil], nil];
NSArray *ar2 = [NSArray arrayWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:@"Musical instrument",@"category",@"2013-09-27T06:02:28+0000",@"created_time",@"113099055370169",@"id", @"Guitar",@"name", nil], nil];
NSMutableSet* set1 = [NSMutableSet setWithArray:ar1];
NSMutableSet* set2 = [NSMutableSet setWithArray:ar2];
[set1 unionSet:set2]; //this will give you only the obejcts that are in both sets
NSArray* result = [set1 allObjects];
NSLog(@"%@",[result mutableCopy]);
快樂編碼!!!
假設您只需要比較“ id”值:
NSArray* myIds = [arrMyInterest valueForKey:@"id"];
for (int count = 0; count < [arrFriendsInterest count]; count++) {
NSDictionary *dictFriend = [arrFriendsInterest objectAtIndex:count];
// Not clear whether "id" is NSString or NSNumber -- use whichever
NSString* friendId = [dictFriend valueForKey:@"id"];
if ([myIds containsObject:friendId]) {
[arrMutualInterest addObject:dictFriend];
}
}
為什么不使用自定義類而不是使用NSDictionary?
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