如何从MySQL Date获得客户年龄

Question

birthday
------------
1988-10-09
1919-12-12

如何正确计算年龄并四舍五入？

我有这个：

SELECT
ROUND((TO_DAYS(NOW()) - TO_DAYS(birthday)) / 365)
FROM customer

有没有更准确的东西？

Answer 1

SELECT TIMESTAMPDIFF(YEAR, birthday, CURDATE()) AS age
FROM customer

资源

SQLFiddle演示

Answer 2

您可以使用datediff()函数获取两个日期之间的天数。 得出结果的底限为您提供年龄的整数部分。

SELECT FLOOR(DATEDIFF(CURDATE(),birthday) / 365) as customer_age
FROM costumer

Answer 3

这是另一个选择：

 SELECT ROUND(DATE_DIFF(NOW(), birthday) / 365) AS age FROM customer

Answer 4

SELECT TIMESTAMPDIFF(YEAR,birthday,NOW()) AS age FROM customer;

Answer 5

这对您有帮助

select DATEDIFF(customer.dob, '2013-10-01') / 365.25 as age

SELECT DATE_FORMAT(FROM_DAYS(DATEDIFF(customer.dob,'2013-10-01')), ‘%Y’)+0 AS age