如何從MySQL Date獲得客戶年齡

Question

birthday
------------
1988-10-09
1919-12-12

如何正確計算年齡並四舍五入？

我有這個：

SELECT
ROUND((TO_DAYS(NOW()) - TO_DAYS(birthday)) / 365)
FROM customer

有沒有更准確的東西？

Answer 1

SELECT TIMESTAMPDIFF(YEAR, birthday, CURDATE()) AS age
FROM customer

資源

SQLFiddle演示

Answer 2

您可以使用datediff()函數獲取兩個日期之間的天數。 得出結果的底限為您提供年齡的整數部分。

SELECT FLOOR(DATEDIFF(CURDATE(),birthday) / 365) as customer_age
FROM costumer

Answer 3

這是另一個選擇：

 SELECT ROUND(DATE_DIFF(NOW(), birthday) / 365) AS age FROM customer

Answer 4

SELECT TIMESTAMPDIFF(YEAR,birthday,NOW()) AS age FROM customer;

Answer 5

這對您有幫助

select DATEDIFF(customer.dob, '2013-10-01') / 365.25 as age

SELECT DATE_FORMAT(FROM_DAYS(DATEDIFF(customer.dob,'2013-10-01')), ‘%Y’)+0 AS age