How to get customers age from MySQL Date

Question

birthday
------------
1988-10-09
1919-12-12

How to calculate the age properly and rounded?

I have this:

SELECT
ROUND((TO_DAYS(NOW()) - TO_DAYS(birthday)) / 365)
FROM customer

Is there something more accurate?

Answer 1

SELECT TIMESTAMPDIFF(YEAR, birthday, CURDATE()) AS age
FROM customer

Source

SQLFiddle demo

Answer 2

You can use datediff() function to get day count between two dates. Flooring the result gives you the integer part of the age.

SELECT FLOOR(DATEDIFF(CURDATE(),birthday) / 365) as customer_age
FROM costumer

Answer 3

这是另一个选择：

 SELECT ROUND(DATE_DIFF(NOW(), birthday) / 365) AS age FROM customer

Answer 4

SELECT TIMESTAMPDIFF(YEAR,birthday,NOW()) AS age FROM customer;

Answer 5

This would be helpful for you

select DATEDIFF(customer.dob, '2013-10-01') / 365.25 as age

SELECT DATE_FORMAT(FROM_DAYS(DATEDIFF(customer.dob,'2013-10-01')), ‘%Y’)+0 AS age