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[英]How do I copy files from the current directory, but not sub-directories using a batch script?
[英]How to create directory junctions for multiple sub-directories using PowerShell?
有很多子文件夹,只能为二阶子文件夹创建目录连接。
当前文件夹结构的某些部分如下所示
C:\MainFolder>tree
Folder PATH listing for volume C System
C:.
├───1stSub-FolderA
│ ├───2ndSub-FolderA
│ └───2ndSub-FolderB
└───1stSub-FolderB
├───2ndSub-FolderA
└───2ndSub-FolderB
D:\MainFolder-Copy>tree
Folder PATH listing for volume Dosya
D:.
├───1stSub-FolderA
└───1stSub-FolderB
每个文件夹的手动编码:
C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA C:\MainFolder\1stSub-FolderA\2ndSub-FolderA
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderA
C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB C:\MainFolder\1stSub-FolderA\2ndSub-FolderB
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderB
C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA C:\MainFolder\1stSub-FolderB\2ndSub-FolderA
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderA
C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB C:\MainFolder\1stSub-FolderB\2ndSub-FolderB
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderB
结果:
C:\MainFolder>tree
Folder PATH listing for volume C System
C:.
├───1stSub-FolderA
│ ├───2ndSub-FolderA
│ └───2ndSub-FolderB
└───1stSub-FolderB
├───2ndSub-FolderA
└───2ndSub-FolderB
D:\MainFolder-Copy>tree
Folder PATH listing for volume Dosya
D:.
├───1stSub-FolderA
│ ├───2ndSub-FolderA
│ └───2ndSub-FolderB
└───1stSub-FolderB
├───2ndSub-FolderA
└───2ndSub-FolderB
如何使用几个命令为所有只有二阶子文件夹而不是为每个文件夹手动编写代码? 命令不应为第1,第3,第4,第5 ...订单子文件夹创建目录连接。
尝试这个:
Get-ChildItem D:\MainFolder-Copy -Directory |
Foreach {Get-ChildItem (Join-Path C:\MainFolder $_.Name) -Directory} |
Foreach {cmd /c mklink /j ($_.FullName -replace 'C:\\MainFolder','D:\MainFolder-Copy') $_.FullName}
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