[英]Find the closest value above and under in an array?
我有一个数组,该数组由[元素编号,x坐标,y坐标,z坐标,半径(极坐标),θ(极坐标)]组成。在这个数组中,我需要找到两个最接近指定值的值数字,上面的一个和下面的一个 这需要在保存θ值的数组的最后一列中找到。
值的范围从0-1.5707弧度(0-90度)开始,在我们的情况下,我们希望能够选择所需的指定数字量
number=9
Anglestep = math.pi/2 / number
Anglerange = np.arange(0,math.pi/2+anglestep,anglestep) #math.pi/2+anglestep so that we get math.pi/2 in the array
例如,我需要在指定值的上方和下方找到两个值:“ 0.17”
[...['4549', '4.2158604', '49.4799309', '0.0833661', 49.65920902290997, 0.0849981532744405],
['4535', '4.2867651', '49.4913025', '0.0813997', 49.67660795755971, 0.08640089283783374],
['4537', '5.6042995', '49.4534569', '0.0811241', 49.7699967073121, 0.11284330708918186],
['4538', '6.2840257', '49.4676971', '0.0809942', 49.86523874780516, 0.12635612935285648],
['4539', '6.9654546', '49.4909363', '0.0814121', 49.97869879894153, 0.13982362821749783],
['4540', '7.6476088', '49.5210190', '0.0813955', 50.10805567128103, 0.1532211602749019],
['4541', '8.3298655', '49.5605049', '0.0812513', 50.25564948531672, 0.16651831290560243],
['4542', '9.0141211', '49.6065178', '0.0811457', 50.41885547537927, 0.17975113416156624],
['4529', '9.3985014', '49.6320610', '0.0812080', 50.51409018950577, 0.18714756393388338],
['4531', '10.3884563', '49.7157669', '0.0812043', 50.78954127329902, 0.2059930152826599]..]
所以在这种情况下,我想要作为输出的是两个值:(0.16651831290560243,0.17975113416156624)
In [30]: np.max(arr[arr < .17])
Out[30]: 0.16651831290560243
In [31]: np.min(arr[arr > .17])
Out[31]: 0.17975113416156624
@NPE的答案对于一维数组是正确的,但是必须首先访问数组的Angle
列。 这取决于数组的dtype
(数据类型)(您的数组似乎包含字符串和浮点数,对于numpy数组是不允许的)。 有两种解决方法,一种是全部浮动,另一种是使用结构化dtype:
arr = np.array([
['4549', '4.2158604', '49.4799309', '0.0833661', 49.65920902290997, 0.0849981532744405 ],
['4535', '4.2867651', '49.4913025', '0.0813997', 49.67660795755971, 0.08640089283783374],
['4537', '5.6042995', '49.4534569', '0.0811241', 49.7699967073121 , 0.11284330708918186],
['4538', '6.2840257', '49.4676971', '0.0809942', 49.86523874780516, 0.12635612935285648],
['4539', '6.9654546', '49.4909363', '0.0814121', 49.97869879894153, 0.13982362821749783],
['4540', '7.6476088', '49.5210190', '0.0813955', 50.10805567128103, 0.1532211602749019 ],
['4541', '8.3298655', '49.5605049', '0.0812513', 50.25564948531672, 0.16651831290560243],
['4542', '9.0141211', '49.6065178', '0.0811457', 50.41885547537927, 0.17975113416156624],
['4529', '9.3985014', '49.6320610', '0.0812080', 50.51409018950577, 0.18714756393388338],
['4531', '10.3884563', '49.7157669', '0.0812043', 50.78954127329902, 0.2059930152826599 ]], dtype=float)
然后,应用@Jaime的方法 ,使用
i = np.searchsorted(arr[:, -1], 0.17)
below = arr[i-1]
above = arr[i]
below
# array([ 4.54100000e+03, 8.32986550e+00, 4.95605049e+01, 8.12513000e-02, 5.02556495e+01, 1.66518313e-01])
above
# array([ 4.54200000e+03, 9.01412110e+00, 4.96065178e+01, 8.11457000e-02, 5.04188555e+01, 1.79751134e-01])
如果只需要角度,那么也可以按列分割:
below_ang = arr[i-1, -1]
above_ang = arr[i, -1]
below_ang, above_ang
#(0.166518313, 0.179751134)
注意,这假定arr
按角度排序。
arr = array([ ('4549', '4.2158604', '49.4799309', '0.0833661', 49.65920902290997, 0.0849981532744405 ),
('4535', '4.2867651', '49.4913025', '0.0813997', 49.67660795755971, 0.08640089283783374),
('4537', '5.6042995', '49.4534569', '0.0811241', 49.7699967073121 , 0.11284330708918186),
('4538', '6.2840257', '49.4676971', '0.0809942', 49.86523874780516, 0.12635612935285648),
('4539', '6.9654546', '49.4909363', '0.0814121', 49.97869879894153, 0.13982362821749783),
('4540', '7.6476088', '49.5210190', '0.0813955', 50.10805567128103, 0.1532211602749019 ),
('4541', '8.3298655', '49.5605049', '0.0812513', 50.25564948531672, 0.16651831290560243),
('4542', '9.0141211', '49.6065178', '0.0811457', 50.41885547537927, 0.17975113416156624),
('4529', '9.3985014', '49.6320610', '0.0812080', 50.51409018950577, 0.18714756393388338),
('4531', '10.3884563', '49.7157669', '0.0812043', 50.78954127329902, 0.2059930152826599)],
dtype=[('id', 'S4'), ('x', 'S10'), ('y', 'S10'), ('z', 'S9'), ('rad', '<f8'), ('ang', '<f8')])
i = np.searchsorted(arr['ang'], 0.17)
below = arr[i-1]
above = arr[i]
below
# ('4541', '8.3298655', '49.5605049', '0.0812513', 50.25564948531672, 0.16651831290560243)
above
# ('4542', '9.0141211', '49.6065178', '0.0811457', 50.41885547537927, 0.17975113416156624)
首先,使用linspace
可以更轻松地设置范围,该方法自动包含开始和结束,并由数组的长度而不是步长指定。 代替:
number=9
anglestep = math.pi/2 / number
anglerange = np.arange(0,math.pi/2+anglestep,anglestep) #math.pi/2+anglestep so that we get math.pi/2 in the array
采用
number = 9
anglerange = np.linspace(0, math.pi/2, number) # start, end, number
现在, searchsorted
实际上将为您轻松找到几个要点:
locs = np.searchsorted(arr['ang'], anglerange)
belows = arr['ang'][locs-1]
aboves = arr['ang'][locs]
例如,我将把anglerange = [0.1, 0.17, 0.2]
设置anglerange = [0.1, 0.17, 0.2]
因为整个范围不在您的样本数据中:
belows
# array([ 0.08640089, 0.16651831, 0.18714756])
aboves
# array([ 0.11284331, 0.17975113, 0.20599302])
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