检查列表中是否存在值为x的namedtuple

Question

我想看看列表中是否存在一个namedtuple，类似于：

numbers = [1, 2, 3, 4, 5]
if 1 in numbers:
      do_stuff()

是否有pythonic（或非）方式这样做？ 就像是：

 namedtuples = [namedtuple_1, namedtuple_2, namedtuple3]
 if (namedtuple with value x = 1) in namedtuples:
      do stuff()

Answer 1

使用any ：

演示：

>>> from collections import namedtuple
>>> A = namedtuple('A', 'x y')
>>> lis = [A(100, 200), A(10, 20), A(1, 2)]
>>> any(a.x==1 for a in lis)
True
>>> [getattr(a, 'x')==1 for a in lis]
[False, False, True]