[英]Get values from xml file using lxml
作为将用户配置存储到数据库的替代方法,我现在选择将那些配置存储在xml文件中。 使用lxml
,我创建了以下示例(示例):
<root>
<trigger name="trigger_a">
<config_a>10</config_a>
<config_b>4</config_b>
<config_c>true</config_c>
</trigger>
<trigger name="trigger_b">
<config_a>11</config_a>
<config_b>5</config_b>
<config_c>false</config_c>
</trigger>
</root>
所以我的目的是给我想要的触发器名称,以获得相关的配置。 像这样的例子:
print getTriggerConfig('trigger_a')
Config a is: 10
Config b is: 4
Config c is: true
提前致谢。
编辑:我不希望你们给我完整的解决方案。 我找到了此链接“ 如何在Python中获取XML标记值”,该链接显示了我的操作方法,但是我创建了此文章,以查看是否有比给出的答案“更干净”的东西。 另外,由于我已经在使用lxml
所以我不想使用BeautifulSoup
。
这是基本思想(
未经
测试):
from lxml import etree
f = """<root>
<trigger name="trigger_a">
<config_a>10</config_a>
<config_b>4</config_b>
<config_c>true</config_c>
</trigger>
<trigger name="trigger_b">
<config_a>11</config_a>
<config_b>5</config_b>
<config_c>false</config_c>
</trigger>
</root>"""
tree = etree.XML(f)
# uncomment the next line if you want to parse a file
# tree = etree.parse(file_object)
def getTriggerConfig(myname):
# here "tree" is hardcoded, assuming it is available in the function scope. You may add it as parameter, if you like.
elements = tree[0].xpath("//trigger[@name=$name]/*", name = myname)
# If reading from file uncomment the following line since parse() returns an ElementTree object, not an Element object as the string parser functions.
#elements = tree.xpath("//trigger[@name=$name]/*", name = myname)
for child in elements:
print("Config %s is: %s"%(child.tag[7:], child.text))
用法:
getTriggerConfig('trigger_a')
收益:
Config a is: 10
Config b is: 4
Config c is: true
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