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[英]Using Python LXML to removing XML element values but leaving one placeholder
[英]Reading element values from XML using Python LXML
<markets xmlns="http://www.eoddsmaker.net/schemas/markets/1.0" D="2015-03-23T23:12:34" CNT="1521">
<S I="50" N="Football">
<C I="65" N="Russia">
<L I="167" N="Premier League">
<E I="1049367" DT="2015-04-05T15:00:00" ISH="0" BKS="20" T1="Ufa" T2="Terek Groznyi" T1I="79698" T2I="44081">
<M K="1x2">
<B I="81" BTDT="2015-03-23T23:04:00,825">
<O N="1" V="3"/>
<O N="X" V="3.1"/>
<O N="2" V="2.25"/>
</B>
</M>
</E>
</L>
</C>
</S>
</markets>
我正在尝试使用Python中的etree解析此XML。 我之前已经做过XML解析,但是文档始终采用这种格式。
<tag> value </tag>
我不确定如何将“ D”与“市场”以及所有其他值区分开。
这就是我打开和解析XML文档的方式:
z = gzip.open("code2.zip", "r")
tree = etree.parse(z)
print(etree.tostring(tree, pretty_print=True))
我试过了:
for markets in tree.findall('markets'):
print "found"
但是,这不起作用。 我将不胜感激一些提示/建议。 希望一旦我提取了第一个“ D”,我就能得到其余的。
在处理具有默认名称空间的 XML时,这是一个常见错误。 您的XML具有默认的命名空间,在此声明为不带前缀的命名空间:
的xmlns = “http://www.eoddsmaker.net/schemas/markets/1.0”
因此,在您的情况下,所有元素都会隐式考虑在该命名空间中。 一种使用xpath()
查询名称空间中元素的可能方法:
.......
#creating prefix-to-namespace_uri mapping
ns = {'d' : 'http://www.eoddsmaker.net/schemas/markets/1.0'}
#use registered prefix along with the element name to query, and pass the mapping as 2nd argument
markets = tree.xpath('//d:markets', namespaces=ns)[0]
#get and print value of D attribute from <markets> :
print markets.get('D')
我在不了解etree的情况下回答了这个问题。 我只是打开了以下页面: https : //docs.python.org/2/library/xml.etree.elementtree.html#parsing-xml
您正在寻找的是属性,并且向您展示了如何非常清楚地推导出它们:
tree = etree.parse(z)
root = tree.getroot()
print root.attrib
您具有<markets>
元素的所有属性,例如D和CNT。
您应该能够自己找出其余的部分。 您只需要遍历每个元素的子元素并从每个元素中获取.attrib
。
考虑到我很容易找到这个答案,请在发布问题之前做一些研究:)
PS此答案是为python 2.7编写的。 对于Python 3,它将为print(tree.attrib)
试试xml.etree
import xml.etree.ElementTree as ET
root = ET.fromstring("""<markets xmlns="http://www.eoddsmaker.net/schemas/markets/1.0" D="2015-03-23T23:12:34" CNT="1521">
<S I="50" N="Football">
<C I="65" N="Russia">
<L I="167" N="Premier League">
<E I="1049367" DT="2015-04-05T15:00:00" ISH="0" BKS="20" T1="Ufa" T2="Terek Groznyi" T1I="79698" T2I="44081">
<M K="1x2">
<B I="81" BTDT="2015-03-23T23:04:00,825">
<O N="1" V="3"/>
<O N="X" V="3.1"/>
<O N="2" V="2.25"/>
</B>
</M>
</E>
</L>
</C>
</S>
</markets>""")
>>>print root.attrib
{'CNT': '1521', 'D': '2015-03-23T23:12:34'}
>>>print root[0].attrib
{'I': '50', 'N': 'Football'}
#and so on to next parse next line
如果需要从xml
文件解析 。
import xml.etree.ElementTree as ET
tree = ET.parse('file.xml')
root = tree.getroot()
有关更多信息,请参见https://docs.python.org/2/library/xml.etree.elementtree.html
print markets.get('D');
在市场(根)上打印“ D”
for element in tree.iterfind(".//{*}<Tag to search for>"):
print element.get("<Attribute to look for>");
将遍历当前节点封装的XML文件中的元素,并在iterfind()中打印每个元素的指定属性。
例如:
for element in tree.iterfind(".//{*}O"):
print element.get("N");
将打印
1
X
2
还要注意,如果XML文档中有多个名称空间,则必须在大括号中指定传递给iterfind()的字符串中的字符串,以匹配要在其下搜索的名称空间。
for element in tree.iterfind(".//{http://www.eoddsmaker.net/schemas/markets/1.0}<Tag to search for>"):
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