![](/img/trans.png)
[英]Boolean Logic question: can I coerce these 4 if statements into a single boolean statement?
[英]How can I join multiple count() statements into a single statement
我有一个名为Resources的表,它有一个名为resourceType的字段。 我需要检索每种资源类型的计数。 目前,我正在使用实体框架在asp.net mvc中执行以下操作:
string[] notservers = new string[] { "vmware virtual platform", "storage device", "router", "switch", "firewall" };
string[] types = new String[] { "server", "workstation" };
IT360ServerNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && (a.SystemInfo.ISSERVER == true ) && !(notservers.Contains(a.SystemInfo.MODEL.Trim().ToLower()))).Count(),
IT360VMNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && (a.SystemInfo.ISSERVER == true) && a.SystemInfo.MODEL.Trim().Equals("VMware Virtual Platform", StringComparison.OrdinalIgnoreCase)).Count(),
IT360SDNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Storage Device", StringComparison.OrdinalIgnoreCase)).Count(),
IT360SwitchNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Switch", StringComparison.OrdinalIgnoreCase)).Count(),
IT360FirewallNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Firewall", StringComparison.OrdinalIgnoreCase)).Count(),
IT360RouterNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Router", StringComparison.OrdinalIgnoreCase)).Count(),
我的视图模型类,如下所示:
public class SystemInformation
{
[Display(Name = "Server/s")]
public int IT360ServerNo { get; set; }
[Display(Name = "VM/s")]
public int IT360VMNo { get; set; }
[Display(Name = "SD/s")]
public int IT360SDNo { get; set; }
[Display(Name = "Switch/s")]
public int IT360SwitchNo { get; set; }
[Display(Name = "Firewall/s")]
public int IT360FirewallNo { get; set; }
[Display(Name = "Router/s")]
public int IT360RouterNo { get; set; }
}
但是我的代码将向数据库发送6个请求,以分别检索每种类型的计数。 那么有没有办法写一条语句使Resource表根据类型分组并为每种类型检索Count()? 谢谢
编辑:-这就是我填充模型类的方式:-
public SystemInformation GetSystemInfo(int pagesize)
{
var d = DateTime.Today;
string[] notservers = new string[] { "vmware virtual platform", "storage device", "router", "switch", "firewall" };
string[] types = new String[] { "server", "workstation" };
var tmpCustomCount = tms.CustomAssets.Sum(a => (int?)a.Quantity);
SystemInformation s = new SystemInformation()
{
AssetCount = new AssetCount() {
CustomerCount = entities.AccountDefinitions.Count(),
RackCount = tms.TMSRacks.Count(),
ServerCount = tms.TMSServers.Count(),
VirtualMachineCount = tms.TMSVirtualMachines.Count(),
StorageDeviceCount = tms.TMSStorageDevices.Count(),
FirewallCount = tms.TMSFirewalls.Count(),
SwitchCount = tms.TMSSwitches.Count(),
RouterCount = tms.TMsRouters.Count(),
DataCenterCount = tms.DataCenters.Count(),
CustomCount = tmpCustomCount == null ? 0 : tmpCustomCount.Value
//tms.CustomAssets==null? 0 : tms.CustomAssets.Sum(a => a.Quantity)
},
AdminAudit = AllIncludingAdminAudit("", auditinfo => auditinfo.SecurityTaskType, auditinfo2 => auditinfo2.AuditAction).OrderByDescending(a => a.DateTimeStart)
.Take(pagesize).ToList(),
LatestTechnology = tms.Technologies.Where(a=> !a.IsDeleted && a.IsCompleted).OrderByDescending(a => a.TechnologyID).Take(pagesize).ToList(),
IT360ServerNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && (a.SystemInfo.ISSERVER == true ) && !(notservers.Contains(a.SystemInfo.MODEL.Trim().ToLower()))).Count(),
IT360VMNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && (a.SystemInfo.ISSERVER == true) && a.SystemInfo.MODEL.Trim().Equals("VMware Virtual Platform", StringComparison.OrdinalIgnoreCase)).Count(),
IT360SDNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Storage Device", StringComparison.OrdinalIgnoreCase)).Count(),
IT360SwitchNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Switch", StringComparison.OrdinalIgnoreCase)).Count(),
IT360FirewallNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Firewall", StringComparison.OrdinalIgnoreCase)).Count(),
IT360RouterNo = entities.Resources
.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && a.SystemInfo.MODEL.Trim().Equals("Router", StringComparison.OrdinalIgnoreCase)).Count(),
DeleteNo = tms.TechnologyAudits.Where(a => ( EntityFunctions.TruncateTime(a.DateTimeEnd) == d && a.AuditAction.Name.ToLower() == "delete" && a.TechnologyID != null)).Count(),//TechnologyId != null so that only assets that have tags will be included in the count
CreateNo = tms.TechnologyAudits.Where(a => (EntityFunctions.TruncateTime(a.DateTimeEnd) == d && a.AuditAction.Name.ToLower() == "add" && a.TechnologyID != null)).Count(),
EditNo = tms.TechnologyAudits.Where(a => (EntityFunctions.TruncateTime(a.DateTimeEnd) == d && a.AuditAction.Name.ToLower() == "Edit" && a.TechnologyID != null)).Count(),
OtherNo = tms.TechnologyAudits.Where(a => (EntityFunctions.TruncateTime(a.DateTimeEnd) == d
&&
!((a.AuditAction.Name.ToLower() == "delete" && a.TechnologyID != null)
|| (a.AuditAction.Name.ToLower() == "add" && a.TechnologyID != null)
|| (a.AuditAction.Name.ToLower() == "edit" && a.TechnologyID != null)))).Count(),
};
return s;
你可以用let
语句来做
var systemInformation = (from r in entities.Resources
let serverNos = r.Where(a => String.IsNullOrEmpty(a.ASSETTAG) && (a.SystemInfo.ISSERVER == true ) && !(notservers.Contains(a.SystemInfo.MODEL.Trim().ToLower())))
let vmnos = r.[...]
select new SystemInformation
{
IT360ServerNo = serverNos.Count(),
IT360VMNo = vmnos.Count(),
[...]
}).First();
var assets = entities.Resources.Where(a => String.IsNullOrEmpty(a.ASSETTAG)).ToList()
然后使用资产。在此...将导致一个查询。 然后您的应用程序将对它们进行排序和计数,而不是对数据库进行计数...
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.