将结构的枚举传递给其他函数并分配值

Question

我正在用C ++编写Snake游戏，我有一条蛇的一部分结构，其中包含诸如x位置，y位置，方向等数据。

我已经全部工作了，将所有数据设置为整数，我只是想将某些数据类型更改为枚举，因为它看起来更加整洁并且易于理解。 我已经尝试了很多并在网上查看，但似乎找不到任何东西。

这是一些结构：

struct SnakeSection
{
    int snakePosX;
    int snakePosY;

    int SectionType;
    // Tail = 0, Body = 1, Head = 2

    int animation;

  enum Direction
  {
      Up = 0,
      Right = 1,
      Down = 2,
      Left = 3
  };
};

我试图将指令之一传递给另一个功能的尝试：

void PlayerSnake::createSnake()
{
// Parameters are direction, x and y pos, the blocks are 32x32
addSection(SnakeSection::Direction::Right, mStartX, mStartY, 2);
}

然后，我尝试将方向设置为该函数中传入的方向：

void PlayerSnake::addSection(SnakeSection::Direction dir, int x, int y, int type)
{
    //Create a temp variable of a Snake part structure
    SnakeSection bufferSnake;

    bufferSnake.Direction = dir;
    bufferSnake.animation = 0;

    //is it head tail or what? This is stored in the Snake section struct
    //TODO Add different sprites for each section
    bufferSnake.SectionType = type;

    //assign the x and y position parameters to the snake section struct buffer
    bufferSnake.snakePosX = x;
    bufferSnake.snakePosY = y;

    //Push the new section to the back of the snake.
    lSnake.push_back(bufferSnake);
}

错误：无效使用枚举SnakeSection :: Direction

谢谢

Answer 1

下一行的错误...

bufferSnake.Direction = dir;

...是有道理的，除了声明enum类型外，您还必须具有一个类成员变量来存储它：

struct SnakeSection
{
    int snakePosX;
    int snakePosY;

    int SectionType;
    // Tail = 0, Body = 1, Head = 2

    int animation;

  enum Direction
  {
      Up = 0,
      Right = 1,
      Down = 2,
      Left = 3
  };

  Direction direction_; // <<<<<<<<<<<<<< THAT'S WHAT'S MISSING IN YOUR CODE
};

并参考

bufferSnake.direction_= dir; // <<<<<<<<<<<<<< THAT'S THE MEMBER VARIABLE YOU'LL 
                             //                HAVE TO REFER TO!